Answer:
C-14 => N-14 + β⁻
Explanation:
C-14 over time decays by beta emission to N-14. Before decay, C-14 nucleus contains 6 protons and 8 neutrons. It is accepted that a neutron (n°) is composed of 1 proton (p⁺) and 1 electron (e⁻). Beta emission indicates loss/discharge of a high energy e⁻ from the nucleus of C-14 leaving 7 protons and 7 neutrons. The number of protons defines the element, N-14 as a product of the decay process with the β particle (high energy electron) the other. To check, remember, the ∑mass Reactants = ∑mass Products (superscript numbers) and ∑reactant charges = ∑product charges (subscript numbers
₆C¹⁴ => ₇N¹⁴ + ₋₁e° or, C-14 => N-14 + β
Answer:
Percentage Yield is calculated by doing -> experimental/theoretical x 100% = percentage yield.
I THINK that if your questions are connected it should be 14/16.89 x 100% = 82.889%
Explanation:
<em>Answer:</em>
Symbol = I
<em>Explanation:</em>
<em>Isotopes</em> are those substances which have same atomic number (Numbers of protons) and different masses (Number of proton + numbers of neutrons).
- Iodine also have many isotopes like
<em>Iodine-125</em> that contain 53 protons, 72 neutrons.
<em>Iodine-128</em> that contain 53 protons, 75 neutrons.
<em>Iodine-129 </em> that contain 53 protons, 76 neutrons.
<em>Iodine-131</em> that contain 53 protons, 78 neutrons.
<em>Summary:</em>
- Here the Iodine-131 is correct answer of this question.
I think maybe 2.5
Hope this helps