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HACTEHA [7]
3 years ago
12

Write an algebraic expression with the variable x that has a value of 3 when evaluated

Mathematics
1 answer:
kari74 [83]3 years ago
7 0
X=23

(x+5) - 25 = 3?

If this is what you mean.
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Simplify the expression.
Doss [256]
Distribute 6 thru the parenthesis=

198 pie plus 6 pie

Factor out the perfect square=
Pie 3 to the second power times 22 plus 7 pie 6

Calculate the square root =

3 pie 22 plus 7 pie 6

Which equals to 31.2177

5 0
3 years ago
How old would I be if I was born in 1921
earnstyle [38]
2016 - 1921 = 95
Hope this helped!
6 0
3 years ago
Help please! Question is in picture
netineya [11]

39 ft of carpet

11x3+3x2=39

3 0
3 years ago
Solve 4 cos2x-3 = 0 for all real values of x.
vichka [17]

4 cos² x - 3 = 0

4 cos² x = 3

cos² x = 3/4

cos x = ±(√3)/2

Fixing the squared cosine doesn't discriminate among quadrants.  There's one in every quadrant

cos x = ± cos(π/6)

Let's do plus first.  In general, cos x = cos a has solutions x = ±a + 2πk integer k

cos x = cos(π/6)

x = ±π/6 + 2πk

Minus next.

cos x = -cos(π/6)

cos x = cos(π - π/6)

cos x = cos(5π/6)

x = ±5π/6 + 2πk

We'll write all our solutions as

x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k

3 0
3 years ago
Click the picture for the question please help!!!
sesenic [268]

Answer:

297.33 m

Step-by-step explanation:

3 0
3 years ago
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