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3 years ago

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there were a total of 68 basketball games during the lockout-shortened 2012 NBA season. this season was played over the course o

f five months including playoffs in the NBA Finals .how many basketball games were played each month, ifeach week has the same number games?

1 answer:

alexandr402 [8]3 years ago

6 0

13.4 I'm pretty sure

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2,99,790,000 in scientific notation

ludmilkaskok [199]

So we have 299790000, we want to have only one digit in front of the decimal, 2.9979x10^9

hope this helps :)

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3 years ago

What digit could be in the ten millions place of a number that is less than 55,000,000 but greater than 25,000,000

e-lub [12.9K]

The digit in the ten millions place of a number that is less than 55,000,000 but greater than 25,000,000 can be 3 or 4.

25,000,000 < <u>3</u>5,000,000 < 55,000,000
25,000,000 < <u>4</u>5,000,000 < 55,000,000

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3 years ago

What’s 2+2 because I need help

nikklg [1K]

4 is the answer because it’s just common sense

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3 years ago

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A sample originally contains 21 grams of a radioactive isotope. After 45 days, 17.3 grams of the isotope remain in the sample.

Darya [45]

Answer:

The answer to your question is: 128 days

Step-by-step explanation:

Data

original mass = 21 g

after 45 days = 17.3 g

Process

mass transform = 21 - 17.3 = 3.7 g

21 g ----------------------- 100 %

3.7 g --------------------- x

x = (3.7 x 100) / 21

x = 17.61 %

17.61 % ------------------- 45 days

50% -------------------- x

x = (50 x 45) / 17.61

x = 127.8 ≈ = 128 days

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3 years ago

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Let X equal the number of flips of a fair coin that are required to observe

Nataliya [291]

Answer:

(a) I attached a photo with the diagram.

(b) $f(x) = \big( \frac{1}{2} \big)^{x-1}$

(c) 1/4

(d) 4

(e) $k^2/2$

Step-by-step explanation:

(a) I attached a photo with the diagram.

(b) The easiest way to think about this part is in terms of combinatorics. Think about it like this.

To begin with, look at the three each level of the three represents a possible outcome of throwing the coin n-times. If you throw the coin 3 times at the end in total there are 8 possible outcomes. But The favorable outcomes are just 2.

1 - Your first outcome is HEADS and all the others are different except the last one.

2 - Your first outcome is TAILS and all the others are different except the last one.

Therefore the probability of the event is

$f(x) = P(X=x) = \frac{2}{2^x} = \frac{1}{2^{x-1}} = \big( \frac{1}{2} \big)^{x-1}$

(c)

P(X = 0) = 0 because it is not possible to have two consecutive tails or heads.

$E(X > 4) = 1 - P(X \leq 3) = 1 - ( P(X = 0 ) + P(X = 1) + P(X = 2) + P(X = 3))\\= 1 - ( \frac{1}{2} + \frac{1}{4} ) = \frac{1}{4}$

(d)

Remember that this is a geometric distribution therefore

$E[X] = p/(1-p)$ , in this case $p = 1/2$ so $E[X] = 1$ and

$E[X+1]^2 = ( E[X] +1 )^2 = (1+1)^2 = 2^2 = 4$

Also

(e)

This is a geometric distribution so its variance is

$Var(X) = \frac{1-p}{p^2} = 1/2 / 1/4 = 1/2$

And using properties of variance

$Var(kX - k ) = Var(kX) = k^2 var(X) = k^2 /2$

3 0

3 years ago