The balanced equation for reaction of solid cesium with liquid water
= 2Cs + 2H2O → 2CsOH + H2
cesium react with liquid water to produce cesium hydroxide and hydrogen gas
that is 2 moles of Cs react 2 moles of H2O to form 2 moles CsOH and 1 of hydrogen gas
Answer:
(R)-but-3-en-2-ylbenzene
Explanation:
In this reaction, we have a very <u>strong base</u> (<em>sodium ethoxide</em>). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an <u>E2 mechanism</u>, therefore, the hydrogen that is removed must have an <u>angle of 180º</u> with respect to the leaving group (the "OH"). This is known as the <u>anti-periplanar configuration</u>.
The hydrogen that has this configuration is the one that placed with the <u>dashed bond</u> (<em>red hydrogen</em>). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.
See figure 1
I hope it helps!
Answer: 1 mole of the substance is equal to its molar mass or vice versa.
Explanation: Example: 18 g H2O x 1 mole H2O / 18g H2O = 1 mole H2O
Lithium oxide is able to undergo both the processes of dissolution and dissociation.
Dissociation refers to the break down a chemical substance into its constituents. Ionization refers to the loss of electrons from a chemical specie while dissolving refers to the ability of a solid to form a solution.
Let us now look at each of the following species;
- Lithium oxide undergoes dissolution and dissociation.
- Magnesium nitride undergoes dissolution and dissociation.
- Hydrobromic acid undergoes dissolution and dissociation.
Learn more about ionization: brainly.com/question/1602374