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Scorpion4ik [409]
3 years ago
15

I need help please!!

Chemistry
1 answer:
adell [148]3 years ago
7 0

To start, name the longest carbon chain. This would be the 5-membered chain, so the parent name is “pentane”. All that is left is to address the side substituent, which is a methyl attached at the 3 position, so the final name of the compound is 3-methylpentane.

Hope this helps!

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When 100.g Mg3N2 reacts with 75.0 g H2O, what is the maximum theoretical yield of NH3?
Temka [501]

Answer : The correct option is, 23.6 g

Explanation : Given,

Mass of Mg_3N_2 = 100.0 g

Mass of H_2O = 75.0 g

Molar mass of Mg_3N_2 = 101 g/mol

Molar mass of H_2O = 18 g/mol

First we have to calculate the moles of Mg_3N_2 and H_2O.

\text{Moles of }Mg_3N_2=\frac{\text{Given mass }Mg_3N_2}{\text{Molar mass }Mg_3N_2}

\text{Moles of }Mg_3N_2=\frac{100.0g}{101g/mol}=0.990mol

and,

\text{Moles of }H_2O=\frac{\text{Given mass }H_2O}{\text{Molar mass }H_2O}

\text{Moles of }H_2O=\frac{75.0g}{18g/mol}=4.17mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

Mg_3N_2(s)+6H_2O(l)\rightarrow 3Mg(OH)_2(aq)+2NH_3(g)

From the balanced reaction we conclude that

As, 6 moles of H_2O react with 1 mole of Mg_3N_2

So, 4.17 moles of H_2O react with \frac{4.17}{6}=0.695 moles of Mg_3N_2

From this we conclude that, Mg_3N_2 is an excess reagent because the given moles are greater than the required moles and H_2O is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NH_3

From the reaction, we conclude that

As, 6 moles of H_2O react to give 2 moles of NH_3

So, 4.17 moles of H_2O react to give \frac{2}{6}\times 4.17=1.39 mole of NH_3

Now we have to calculate the mass of NH_3

\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3

Molar mass of NH_3 = 17 g/mole

\text{ Mass of }NH_3=(1.39moles)\times (17g/mole)=23.6g

Therefore, the maximum theoretical yield of NH_3 is, 23.6 grams.

4 0
3 years ago
20 grams of water. She poured out 15 grams. Which of the following physical properties of the water changes?
zlopas [31]

Answer:

Volume  only intrinsic

Explanation:

8 0
4 years ago
48:03
Iteru [2.4K]
The outer is the correct answer
5 0
3 years ago
A container holds 0.490 m3 of oxygen at an absolute pressure of 5.00 atm. A valve is opened, allowing the gas to drive a piston,
mash [69]

<u>Answer:</u> The new volume will be 2.04m^3

<u>Explanation:</u>

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2            (at constant temperature)

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=5.00atm\\V_1=0.490m^3\\P_2=1.20atm\\V_2=?m^3

Putting values in above equation, we get:

5atm\times 0.490m^3=1.20\times V_2\\\\V_2=2.04m^3

Hence, the new volume will be 2.04m^3

5 0
3 years ago
O2 + C3H2 + H2O + CO2<br> Reaction type?
Kobotan [32]

Answer:

Combustion is the reaction type if you meant to put a "=" in between C3H2 and H2O

3 0
4 years ago
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