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PilotLPTM [1.2K]
3 years ago
11

ANWER 3 QUESTIONS WITH THE CORRECT ANSWER 24 POINTS

Physics
2 answers:
steposvetlana [31]3 years ago
4 0
15/ a
16/ b
17/ a

Hope this helps


Xelga [282]3 years ago
3 0
C
A
B
I'm not sure about number 15.
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Use these relationships to determine the number of calories to change 1.5 kg of 0∘c ice water to 1.5 kg of 100∘c boiling water.
aivan3 [116]
The latent heat of fusion of water is 80 cal/g.
The specific heat of water is 1 cal/g-C.
The latent heat of vaporization of water is 540 cal/g.
Therefore, if we have 1.5 kg = 1500 g, the total heat requirement is:
1500 g[(80 cal/g) + (1 cal/g-C)(100 - 0)C + (540 cal/g)] = 1500 g(720 cal/g) = 1,080,000 cal.
4 0
3 years ago
When antimatter interacts with an equal mass of ordinary matter, both matter and antimatter are converted completely into energy
Ilya [14]

Answer:

  v = 5.88 10⁷ m / s

Explanation:

For this exercise we use the relation

          E = m c²

also indicate that all energy is converted into kinetic energy

          E = K = ½ (M-2m) v²

where m is the mass of antimatter and M is the mass of the ship's mass. Factor two is due to the fact that equal amounts of matter and antimatter must be combined

we substitute  

         m c² = ½ (M-2m) v²

        v² = 2 \frac{m}{M+2m} \ c^2

         

let's calculate

        v = \sqrt{2 \  \frac{4 \ 10^4 }{2 \ 10^6 + 2 \ 4 \ 10^4} \ (3 \ 10^8)^2}

         v = \sqrt{ 34.615 \ 10^{14}}

        v = 5.88 10⁷ m / s

8 0
3 years ago
What oxigen rich reaches cells in the body through small blood vessels
kolezko [41]

Answer:

Inside the air sacs, oxygen moves across paper-thin walls to tiny blood vessels called capillaries and into your blood. A protein called haemoglobin in the red blood cells then carries the oxygen around your body.

3 0
3 years ago
If the charge on the negative plate of the capacitor is 121 nano-Coulomb, how many excess electrons are on that plate? Write you
Julli [10]

Answer:

n = 756.25 giga electrons

Explanation:

It is given that,

If the charge on the negative plate of the capacitor, Q=121\ nC=121\times 10^{-9}\ C

Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

Q=ne

e is the charge on electron

n=\dfrac{Q}{e}

n=\dfrac{121\times 10^{-9}}{1.6\times 10^{-19}}

n=7.5625\times 10^{11}

or

n = 756.25 giga electrons

So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.

6 0
4 years ago
A boy drops a 0.10 kg stone down a 150 m well and listens for the echo. The air temperature is 20°C. How long after the stone is
S_A_V [24]
Use formula for Echo which is Velocity=2(Distance)/time so 343=2(150)/T 343T=300..T=300/343=0.9 seconds
4 0
3 years ago
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