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PilotLPTM [1.2K]
3 years ago
11

ANWER 3 QUESTIONS WITH THE CORRECT ANSWER 24 POINTS

Physics
2 answers:
steposvetlana [31]3 years ago
4 0
15/ a
16/ b
17/ a

Hope this helps


Xelga [282]3 years ago
3 0
C
A
B
I'm not sure about number 15.
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dusya [7]

Answer: direct linear

Explanation:

3 0
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What does vf stand for<br> a.fringe velocity<br> b.first velocity<br> c.final velocity
Elza [17]
The correct answer is C. Final Velocity

Hope this helped!
5 0
3 years ago
A _____________ is a system that uses vertical posts which are separated to support a horizontal beam. A. Truss c. Post-and-lint
IgorC [24]

A Post-and-lintel is a system that uses vertical posts which are separated to

support a horizontal beam.

A Post-and-lintel system is commonly used in architecture and involves the

system where horizontal structures are held by vertical ones with the

presence of spaces between them.

In this scenario, we were told the system uses vertical posts which are

separated to support a horizontal beam which makes Post-and-lintel the

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Read more on brainly.com/question/8777125

3 0
2 years ago
An object that is slowing down in a positive direction must have
zepelin [54]

Answer:

Positive velocity and negative acceleration

Explanation:

An object moving in the positive direction has a positive velocity.

An object that's slowing down while moving in the positive direction has a negative acceleration.

5 0
3 years ago
A solid sphere of radius 40.0 cm has a total positive charge of 16.2 μC uniformly distributed throughout its volume. Calculate t
Jobisdone [24]

Answer:

(a) E=0  :   0 cm from the center of the sphere

(b) E= 227.8*10³ N/C   :    10.0 cm from the center of the sphere

(c)E= 911.25*10³ N/C    :    40.0 cm from the center of the sphere

(d)E= 411.84 * 10³ N/C  :    59.5 cm from the center of the sphere

Explanation:

If we have a uniform charge sphere we can use the following formulas to calculate the Electric field due to the charge of the sphere

E=\frac{K*Q}{r^{2} } : Formula (1) To calculate the electric field in the region outside the sphere r ≥ a

E=k*\frac{Q}{a^{3} } *r :Formula (2) To calculate the electric field in the inner region of the sphere. r ≤ a

Where:

K: coulomb constant

a: sphere radius

Q:  Total sphere charge

r : Distance from the center of the sphere to the region where the electric field is calculated

Equivalences

1μC=10⁻⁶C

1cm= 10⁻²m

Data

k= 9*10⁹ N*m²/C²

Q=16.2 μC=16.2 *10⁻⁶C

a= 40 cm = 40*10⁻²m = 0.4m

Problem development

(a)Magnitude of the electric field at  0 cm :

We replace r=0 in the formula (2) , then, E=0

(b) Magnitude of the electric field at 10.0 cm from the center of the sphere

r<a , We apply the Formula (2):

E=9*10^{9} *\frac{16.2*10^{-6} }{0.4^{3} } *0.1

E= 227.8*10³ N/C

(c) Magnitude of the electric field at 40.0 cm from the center of the sphere

r=a, We apply the Formula (1) :

E=\frac{9*10^{9}*16.2*10^{-6} }{0.4^{2} }

E= 911.25*10³ N/C

(d) Magnitude of the electric field at 59.5 cm from the center of the sphere  

r>a , We apply the Formula (1) :

E=\frac{9*10^{9}*16.2*10^{-6} }{0.595^{2} }

E= 411.84 * 10³ N/C

4 0
3 years ago
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