Answer:
0.14 J
Explanation:
The maximum velocity is the amplitude times the angular frequency.
vmax = Aω
ω = vmax / A
ω = (3.2 m/s) / (0.06 m)
ω = 53.3 rad/s
For a spring-mass system:
ω = √(k / m)
ω² = k / m
k = ω²m
k = (53.3 rad/s)² (0.050 kg)
k = 142 N/m
The elastic potential energy is:
EE = ½ kx²
EE = ½ (142 N/m) (0.044 m)²
EE = 0.14 J
Answer:
a) 13I₁ + 18I₂ = 30v
b) 18I₁ - 5I₃ = -12v
c) I₁ = I₂ + I₃
d) I₃ = I₁ - I₂
e) 5I₁ - 23I₂ = 24v
f) I₁ =2.88A
I₂ = -0.41A
g) I₃ = 3.29A
h) I₂ = 1.41A
The significance of the negative sign of I₂ is that the direction of the flow of current I₂ is opposite to the direction assumed.
Explanation:
Answer:
velocity in problems per hour = 4 per hour
so correct option is b. 4 per hour
Explanation:
given data
worked on homework time = 1.5 hour
completed = 6 problems
to find out
What is the velocity in problems per hour
solution
we know that Shirley solve complete 6 accounting homework problem in 1.5 hour so her velocity in problems per hour will be as
velocity in problems per hour = ..................1
put here value we will get
velocity in problems per hour =
velocity in problems per hour = 4 per hour
so correct option is b. 4 per hour
Answer:
43°
Explanation:
Sin tita m= mlambda/d
Sin 20°= lambda/d
Sin tita 2= 2(lambda/d)
Sin tita 2= 2 sin 20
Sin tita 2= 0. 684
Tita 2= sin-1(0. 684)
Tita 2= 43°
Thus, the angle of the second order maximum is 43°