Given that, the height of the tide measured at a seaside community varies according to the number of hours t after midnight. The height is given by the equation as :

$h=-\dfrac{1}{2}t^2+6t-9$

When the tide first be at 6 ft, put h = 6 ft in above equation as :

$-\dfrac{1}{2}t^2+6t-9=6$

$-t^2+12t-18=0$

On solving the above equation to find the value of t. It is equal to :

t = 3.551 seconds

t = 8.449 seconds

So, the tide of 6 ft is at 3.551 seconds and 8.449 seconds. Hence, this is the required solution.

6 0

3 years ago

You can see stars brighter than magnitude +6 with your naked eye under dark sky conditions, and you can also see the full moon a

Mariana [72]

-6 uh 89 0 -+= 62 uwuwhhiwhiuhwiuhwuihhishishoknsk

6 0

3 years ago

Science cannot be used to answer questions about _____.

aksik [14]

Science cannot be used to answer questions about Moral judgements

8 0

3 years ago

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A rocket of mass m is to be launched fromplanet X, which has a mass M and a radius R. What is the minimum speed that the rocket

Sunny_sXe [5.5K]

Answer:

The minimum speed = $\sqrt{\frac{2GM}{R} }$

Explanation:

The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.

The minimum speed can be determined by;

Escape velocity = $\sqrt{\frac{2GM}{R} }$

where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.

If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.

7 0

3 years ago