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2 answers:
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Answer:
a)<em> It took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves. </em>
b) <em>The minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds. </em>
Explanation:
The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensitie. That radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.
The distribution of the radiation in the electromagnetic spectrum can also be given in wavelengths, but it is more frequent to work with it at frequencies:
- Gamma rays
- X-rays
- Ultraviolet rays
- Visible region
- Infrared
- Microwave
- Radio waves.
Any radiation that belongs to electromagnetic spectrum has a speed in vacuum of .
<em>a) Find the time it took for his voice to reach the Earth via radio waves.</em>
To know the time that took for Neil Armstrong's voice to reach the Earth via radio waves, the following equation can be used:
(1)
Where v is the speed of light, d is the distance and t is the time.
Notice that t can be isolated from equation 1.
(2)
The distance from the Earth to the Moon is , therefore.
Hence, it took 1.28 seconds to Neil Armstrong's voice to reach the Earth via radio waves.
<em>b) Determine the minimum time that will be required for a message from Mars to reach the Earth via radio waves.</em>
The distance from the Earth to the Mars at its closest approach is , therefore.
Hence, the minimum time that will be required for a message from Mars to reach the Earth via radio waves is 192 seconds.
Answer:
a) The distance of spectator A to the player is 79.2 m
b) The distance of spectator B to the player is 43.9 m
c) The distance between the two spectators is 90.6 m
Explanation:
a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:
x = v * t
where:
x = position of the spectators
v = speed of sound
t = time
Then, the position for spectator A relative to the player is:
x = 343 m/s * 0.231 s = 79.2 m
b)For spectator B:
x = 343 m/s * 0.128 s
x = 43.9 m
The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.
c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:
(Distance AB)² = A² + B²
(Distance AB)² = (79.2 m)² + (43.9 m)²
Distance AB = 90. 6 m
