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maw [93]
4 years ago
11

Can someone help me, it will get 5 stars

Physics
2 answers:
Tcecarenko [31]4 years ago
6 0

vfdssmnfffffffffffffffffffffffffffffff

erica [24]4 years ago
4 0

Answer:

A. Increased self-esteem

Explanation:

I hope this helps :)

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Extra Practice In Exercises 1-4, use the diagram. 1. Give two other names for CD. <br>​
lana [24]

Answer: I think it’s point cd and line cd

Explanation:

6 0
3 years ago
An official act by the President forgiving a person convicted of a crime and
Igoryamba

Answer:

Pardon

Explanation:

Using the fundamental laws of mass-energy conservation. We can determine that the photon particle is fundamental and delivers the energy required to change the mass of an object into energy.

7 0
3 years ago
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A baseball is thrown straight up. the drag force is proportional to v2. part a in terms of g, what is the y-component of the bal
steposvetlana [31]

At the position of terminal speed the net acceleration of the ball will become zero

As we know that terminal speed will always reach when net force on the ball is zero and its speed will become constant.

So here at this position we can say

F_d = F_g

kv^2 = mg

v =\sqrt{\frac{mg}{k}}

now when ball is moving at half of the terminal speed in upward direction then net force on the ball in downwards direction will be

F_{net} = mg + F_d

F_{net} = mg + kv^2

here speed of the ball is half of the terminal speed

v = \frac{1}{2}*\sqrt{\frac{mg}{k}}

then we have

F_{net} = mg + k*\frac{mg}{4k}

F_{net} = \frac{5mg}{4}

now acceleration will be given as

a = \frac{F_{net}}{m}

now we have

a = \frac{5g}{4}

a = 12.25 m/s^2 downwards

7 0
4 years ago
A ball starts from rest and undergoes uniform acceleration of 2.50m/s^2. What is the velocity of the ball 4s later?
erica [24]

Explanation:

Given:

v₀ = 0 m/s

a = 2.50 m/s²

t = 4 s

Find: v

v = at + v₀

v = (2.50 m/s²) (4 s) + 0 m/s

v = 10 m/s

4 0
3 years ago
Read 2 more answers
Please hurry please
Ghella [55]

Answer:

0.765m

Explanation:

gravitational potential energy GPE = mass * acceleration due to gravity * height

Given

GPE = 30Joules

Mass m = 4kg

acceleration = 9.8m/s²

Required

Height h

From the formula

h = GPE/mg

h = 30/4(9.8)

h = 30/39.2

h = 0.765m\

Hence the height of the counter is 0.765m

4 0
3 years ago
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