A horizontal uniform bar of mass 2.5 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t
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Answer:
(a), The SSD will be 723.9 ft.
(b-1), The SSD will be 620.2 ft.
(b-2), The SSD will be
(c), The SSD will be 910.5 ft.
Explanation:
Given that,
Speed = 70 mph
Suppose, a perception reaction time of 2.5 sec and the coefficient of friction is 0.35
We need to calculate the stopping sight distance
Using formula of SSD
Where, v = speed of vehicle
t = perception reaction time
f = coefficient of friction
g = gradient of road
(a). If the gradient of road is zero.
Then, the stopping sight distance will be
(b-1). If the gradient of road is 0.1
Then, the stopping sight distance will be
(b-2). If the grade continuously decrease then the SSD will be increase.
But if the grade is increase then the SSD will be decrease and for flat grade the SSD will be more.
So, The SSD will be
(c). When the vehicle is traveling downhill on a roadway of constant grade then the vehicle take will be more SSD
So, The SSD will be
Hence, (a), The SSD will be 723.9 ft.
(b-1), The SSD will be 620.2 ft.
(b-2), The SSD will be
(c), The SSD will be 910.5 ft.
Answer:
<h2>Refer the attachment for answer and explanation please</h2>Explanation:
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