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Scrat [10]
4 years ago
6

Use the slit example to explain why you can hear a noise in another room through an open door.

Physics
1 answer:
defon4 years ago
8 0
Because the wall reflects sound waves to your ears bouncing off of the walls, even if it's in another room.
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What are two ways friction can be useful
Mnenie [13.5K]
Gravity is an example of friction.  If we didn't have gravity, we would be flying all over the place.  Also, friction keeps us from sliding on the ground and falling.
4 0
3 years ago
How to prove formula for volume of a sphere ?
atroni [7]

Answer:

The volume of radius is   \frac{4}{3} × π × radius³  Proved

Explanation:

Given as :

We know that volume of sphere is v = \frac{4}{3} × π × radius³

Or, v =  \frac{4}{3} × π × r³

Let prove the volume of sphere

So, From the figure of sphere

At the height of z , there is shaded disk with radius x

Let Find the area of triangle with side x , z , r

<u>From Pythagorean theorem</u>

x² + z² = r²

Or, x² = r² -  z²

Or, x = \sqrt{r^{2}-z^{2}  }

Now, Area of shaded disk = Area = π × x²

Where x is the radius of disk

Or, Area of shaded disk = π × (\sqrt{r^{2}-z^{2}  }) ²

∴ Area of shaded disk = π × (r² - z²)

Again

<u>If we calculate the area of all horizontal disk, we can get the volume of sphere</u>

So, we simply integrate the area of all disk from - r to + r

i.e volume = \int_{-r}^{r} \Pi(r^{2}-z^{2} )dz

Or, v = \int_{-r}^{r} \Pi r^{2}dz - \int_{-r}^{r} \Pi z^{2}dz

Or, v = π r² (r + r) -  π \frac{r^{3} -(-r)^{3})}{3}

Or, v = π r² (r + r) - π \frac{2r^{3}}{3}

Or, v = 2πr³ - π \frac{2r^{3}}{3}

Or, v =  2πr³ (\frac{3-1}{3})

Or, v = 2πr³ × \frac{2}{3}

∴ v =   \frac{4}{3} × π × r³

Hence, The volume of radius is   \frac{4}{3} × π × radius³  Proved . Answer

5 0
3 years ago
A hard rubber ball is thrown level to the ground at a speed of 25 m/s and an initial height of 2.0 meters. Which best describes
Natali [406]
Yes 25.7677 is the amount of motion
7 0
4 years ago
(NEED HELP BADLY)
spin [16.1K]

Answer:

The answer to your question is below

Explanation:

Data 1

mass 1 = 250

mass 2 = 250 kg

gravity constant = 6.67 x 10⁻¹¹ Nm²/kg²

distance = 8 m

Formula

F = G\frac{m1m2}{r^{2} }

Substitution

F = 6.67 x 10^{-11} \frac{250 x 250}{8^{2} }

Result

F = 0.000000065 N

Data 2

mass 1 = 1000 kg

mass 2 = 1000 kg

distance = 5 m

Substitution

F = 6.67 x 10^{-11} \frac{1000 x 1000 }{5^{2} }

Result

F = 0.000002667 N      

8 0
4 years ago
Which of the following is not a true statement
Tresset [83]

Answer:

gadjgdasgdghgsdgd

Explanation:sorry need answer

4 0
4 years ago
Read 2 more answers
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