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4 years ago

6

Use the slit example to explain why you can hear a noise in another room through an open door.

1 answer:

defon4 years ago

8 0

Because the wall reflects sound waves to your ears bouncing off of the walls, even if it's in another room.

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11.) An object that is NOT accelerating could be sitting still or:

Aleonysh [2.5K]

Answer:

moving slowly is the answer

4 0

3 years ago

Read 2 more answers

How is a full moon different from a new moon?

koban [17]

<span>A full moon is at its brightest, and here is no disk to be seen. New moons are barely visable.</span>

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3 years ago

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A jet is circling an airport control tower at a distance of 20.6 km. An observer in the tower watches the jet cross in front of

lesya [120]

Answer:

197.76 m

Explanation:

r = Radius of the path = 20.6 km = $20.6\times 10^3\ m$

$\theta$ = The angle subtended by moon = $9.6\times 10^{-3}\ rad$

Distance traveled is given by

$s=r\times\theta$

$\Rightarrow s=20.6\times 10^3\times 9.6\times 10^{-3}$

$\Rightarrow s=197.76\ m$

The distance traveled by the jet is 197.76 m

8 0

3 years ago

A single sports fan is capable of yelling at an intensity level of 80 decibels from a given distance. If 10,000 similar fans wer

AleksandrR [38]

Answer:

The correct answer is part 'c' 160 dB

Explanation:

When noise levels of different intensities are superimposed the resultant intensity is given by the equation

$L_{avg}=20log(\frac{1}{N}\sum_{i=1}^{N}(10^{\frac{L_{i}}{20}}))\\$

where,

$L_{i}$ is the intensity of a general sound level

Since we have 10000 fans each producing sound of 80dB thus the resultant intensity is given using the above formula as

$L_{avg}=20log(\frac{1}{10000}\sum_{i=1}^{10000}(10^{\frac{80}{20}}))\\$

$\therefore L_{eq}=160dB$

7 0

3 years ago

A single conservative force F(x) = b x + a acts on a 4.37 kg particle, where x is in meters, b = 6.09 N/m and a = 5.96 N. As the

Alenkasestr [34]

Answer:104.41 J

Explanation:

Given

Force acting $F(x)=bx+a$

mass of particle $m=4.37 kg$

$a=5.96 N$

$b=6.09 N/m$

Work done is given by

$W=\int_{a}^{b}F.dx$

$W=\int_{0.652}^{5.1}\left ( 6.09x+5.96\right )dx$

$W=\left [ 6.09\times \left ( \frac{x^2}{2}\right )+5.96\times x\right ]_{0.652}^{5.1}$

$W=77.906+26.51 J$

$W=104.41 J$

4 0

4 years ago