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s2008m [1.1K]
4 years ago
6

When you throw a ball upward, its kinetic energy ____ (DECREASES,INCREASES,REMAINS THE SAME) and its potential energy _____ (DEC

REASE,INCREASES, REMAINS THE SAME) . When the ball reaches maximum height, its kinetic energy is at a ____ (maximum, minimum).
Physics
2 answers:
4vir4ik [10]4 years ago
7 0

When you throw a ball upward, its kinetic energy decreases and its potential energy increases. When the ball reaches maximum height, its kinetic energy is at a minimum.

Explanation:

- When the ball is thrown upward, its kinetic energy decreases. In fact, the kinetic energy of the ball is given by

K=\frac{1}{2}mv^2

where m is the mass of the ball and v its speed. We see that the kinetic energy is directly proportional to the speed: since the speed of the ball decreases as the ball gets higher, its kinetic energy decreases as well.

- the potential energy increases. In fact, the potential energy of the ball is given by

U=mgh

where g is the gravitational acceleration and h is the height above the ground. We see that U is directly proportional to h, therefore as the ball gets higher, h increases and the potential energy increases as well.

- When the ball reaches maximum height, its kinetic energy is minimum. To be more precise, the kinetic energy becomes zero. In fact, at the point of maximum height the speed of the ball becomes zero (because the ball changes direction, it starts going downward), so v=0 in the formula of the kinetic energy and therefore the kinetic energy is zero.

Anettt [7]4 years ago
6 0
When the ball goes upward, the velocity is decreasing. Therefore, the kinetic energy is decreased. The potential energy when the ball's height increases also increases. When the ball reaches maximum, the velocity becomes zero and the kinetic energy is minimum. 
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The correct option is B.
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3 years ago
A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. Which way(s) can increase the c
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Answer:

A, B and F are the right answers

Explanation:

The formula is a_{c} = v^{2} / r

A) Increasing both the radius and the speed by a factor of 9

a_{c} = (9v)^{2} / (9r) = 9v^{2} / r

<u><em>which means the acceleration will increase by a factor of 9</em></u>

B) Keeping the speed fixed and decreasing the radius by a factor of 9

a_{c} = (v)^{2} / (r/9) = 9v^{2} / r

<u><em>which means the acceleration will increase by a factor of 9</em></u>

C) Keeping the radius fixed and increasing the speed by a factor of 9

a_{c} = (9v)^{2} / (r) = 81v^{2} / r

It will increase the acceleration 81 times

D) Keeping the speed fixed and increasing the radius by a factor of 9

a_{c} = (v)^{2} / (9r) = v^{2} / 9r

It will decrease the acceleration by 9 times

E) decreasing both the radius and the speed by a factor of 9

a_{c} = (v/9)^{2} / (r/9) = v^{2} / 9r

It will decrease the acceleration by 9 times

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The voltage across the terminals of a 9.0 v battery is 8.5 v when the battery is connected to a 60 ω load. part a what is the ba
snow_lady [41]
Refer to the diagram shown below.

i = the current in the circuit., A
R₁ = the internal resistance of the battery, Ω
R₂ = the resistance of the 60 W load, Ω

Because the resistance across the battery is 8.5 V instead of 9.0 V, therefore
(R₁ )(i A) = 9 - 8.5 = (0.5 V)
R₁*i = 0.5         (10

Also,
R₂*i = 9.5         (2)

Because the power dissipated by R₂ is 60 W, therefore
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3 0
3 years ago
Read 2 more answers
g A change in the initial _____ of a projectile changes the range and maximum height of the projectile.​
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Answer:

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Explanation:

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As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:

Horizontal range: As per expression:

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Maximum height: As per expression:

H= (u^{2} * sin^{2}θ )/2g

the maximum distance also depends upon square of the initial velocity.

​

​

​

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