1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
6

When you throw a ball upward, its kinetic energy ____ (DECREASES,INCREASES,REMAINS THE SAME) and its potential energy _____ (DEC

REASE,INCREASES, REMAINS THE SAME) . When the ball reaches maximum height, its kinetic energy is at a ____ (maximum, minimum).
Physics
2 answers:
4vir4ik [10]3 years ago
7 0

When you throw a ball upward, its kinetic energy decreases and its potential energy increases. When the ball reaches maximum height, its kinetic energy is at a minimum.

Explanation:

- When the ball is thrown upward, its kinetic energy decreases. In fact, the kinetic energy of the ball is given by

K=\frac{1}{2}mv^2

where m is the mass of the ball and v its speed. We see that the kinetic energy is directly proportional to the speed: since the speed of the ball decreases as the ball gets higher, its kinetic energy decreases as well.

- the potential energy increases. In fact, the potential energy of the ball is given by

U=mgh

where g is the gravitational acceleration and h is the height above the ground. We see that U is directly proportional to h, therefore as the ball gets higher, h increases and the potential energy increases as well.

- When the ball reaches maximum height, its kinetic energy is minimum. To be more precise, the kinetic energy becomes zero. In fact, at the point of maximum height the speed of the ball becomes zero (because the ball changes direction, it starts going downward), so v=0 in the formula of the kinetic energy and therefore the kinetic energy is zero.

Anettt [7]3 years ago
6 0
When the ball goes upward, the velocity is decreasing. Therefore, the kinetic energy is decreased. The potential energy when the ball's height increases also increases. When the ball reaches maximum, the velocity becomes zero and the kinetic energy is minimum. 
You might be interested in
An object weighing 49 N is dropped from a height of 30 m. It is found to be moving with a velocity of 24m/s just before it hits
faltersainse [42]

The  frictional force will be 0.22N.

<h3>What is Frictional force?</h3>

Frictional force is the force generated between two surfaces that are in contact and slide against each other.

Given,

Weight=4N

mass =4.9/9.8=0.5kg

Hieght =30m

velocity=24m/s

Acceration , v²-u²=2as

24²/2×30 =a , u is zero

 a= 1.5m/s²



By Using conservation  of energy ,

30F+1/2mv²=mgh

30F=1150-144

F= 6/30

F=0.2N

The force will be 0.2N

to learn more about Friction clickhttps://brainly.com/question/17608236

#SPJ9

6 0
2 years ago
At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . wh
Anna35 [415]

We have the equation for electric field E = kQ/d^{2}

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to d^{2}

So, \frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

E_{1} = 485 N/C

d_{1} = 0.208 cm

d_{2} = 0.620 cm

E_{2} = ?

\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}

E_{2} = \frac{485*0.208^{2}}{0.628^{2}}

E_{2} = 53.20 N/C

7 0
3 years ago
Read 2 more answers
If the resultant force acting on a 2.0 kg object is equal to (3.0î + 4.0ĵ) N, what is the change in kinetic energy as the object
12345 [234]

Answer:

ΔK = 24 joules.

Explanation:

ΔK = Work done on the object

Work is equal to the dot product of force supplied and the displacement of the object.

W = F * Δs

Δs can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δs = (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).

This gives us

W = < 3, 4 > * < 4, 3 > = (3*4)+(4*3) = 24 J

3 0
1 year ago
A water heater that has the shape of a right cylindrical tank with a radius of 1 foot and a height of 4 feet is being drained. h
Natali5045456 [20]

<span> </span>For any prism-shaped geometry, the volume (V) is assumed by the product of cross-sectional area (A) and height (h). 

<span> V = Ah </span>

<span>
Distinguishing with respect to time gives the relationship between the rates. 
dV/dt = A*dh/dt</span>

<span> in the meantime the area is not altering </span>

<span>
dV/dt = π*(1 ft)^2*(-0.5 ft/min) </span>

<span>
dV/dt = -π/2 ft^3/min ≈ -1.571 ft^3/min 

Water is draining from the tank at the rate of π/2 ft^3/min.</span>

5 0
3 years ago
How can Magnets cause objects to have kinetic energy?
lianna [129]

Answer:

If there is a system of magnets being held in place, there is potential energy. When you let go, the potential energy converts to kinetic energy and the magnets move. Putting the system of magnets close together which creates an opposing force.

Explanation:

4 0
2 years ago
Read 2 more answers
Other questions:
  • The amount of energy the body uses when at rest is referred to as _____.
    8·1 answer
  • Rutherford's atomic theory included which idea?
    13·1 answer
  • What the major difference in PsychologyPsychiatry
    10·1 answer
  • Which statement best explains acceleration? A. It is the total distance covered over a period of time. B. It is a change in velo
    11·2 answers
  • Which of the following BEST describes an object velocity during free fall?
    8·1 answer
  • PLEASE HELP FAST Five-gram samples of brick and glass are at room temperature. Both samples receive equal amounts of energy due
    12·1 answer
  • What's the speed of a sound wave through water at 25 Celsius
    9·1 answer
  • A particular gun (10kg) is able to fire 20 gram bullets at a speed of 350 m/s. From this information, calculate roughly how much
    15·1 answer
  • Divergent plate boundaries are when plates
    15·2 answers
  • A person uses a match to light charcoal in a grill. Which statement describes
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!