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4 years ago

Why do animals that are least specialized have a better chance at survival?

1 answer:

4 0

Animals that are the least specialized generally stand the best chance of survival when the environment suddenly and drastically changes because they're able to (Adapt to different conditions.)

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In a women's 100-m race, accelerating uniformly, Laura takes 2.00 s and Healan 3.00 s to attain their maximum speeds, which they

Sunny_sXe [5.5K]

Complete question is;

In a women’s 100-m race, accelerating uniformly, Laura takes 2.00 s and Healan 3.00 s to attain their maximum speeds, which they each maintain for the rest of the race. They cross the finish line simultaneously, both setting a world record of 10.4 s.

(a) What is the acceleration of each sprinter?

(b) What are their respective maximum speeds?

(d) What is the maximum distance by which Healan is behind Laura, and at what time does that occur?

Answer:

A) a_laura = 5.319 m/s² and a_healan = 3.745m/s²

B) V_max for laura = 10.638 m/s and V_max for Healan = 11.235 m/s

C) Laura is ahead of healan by 2.632 m

D) Healan is 4.471 m behind Laura

Explanation:

A) The distance traveled by each sprinter with constant acceleration would be gotten from the equation of motion which is;

s = ut + ½at²

Now, since they began at rest, thus, initial velocity(u) = 0 m/s

So, s = 0 + ½at²

s = ½at²

Now, maximum speed achieved by each of them is given by the formula;

v_max = u + at

Since u = 0, then;

v_max = at

Now, we are told that they set a world record of 10.4 s, thus;

Time taken by each to run at their maximum speed = (10.4 - t)

Distance travelled after attaining maximum speed = at + a(10.4 - t)

Thus;

Total distance covered by each sprinter = ½at² + (at)(10.4 - t)

Where;

t = time taken to accelerate to maximum speed

Since total distance covered is 100 m and she took 2 s to accelerate to max speed, then Acceleration for Laura would be calculated from;

100 = ½a(2)² + (2a(10.4 - 2))

This gives;

100 = 2a + 16.8a

18.8a = 100

a = 100/18.8

a_laura = 5.319 m/s²

Similarly, for Healan:

100 = ½a(3²) + (3a(10.4 - 3)

100 = 4.5 a + 22.2a

26.7a = 100

a = 100/26.7

a_healan = 3.745m/s²

B) From earlier we saw that max speed is;

v_max = at

Thus, for laura;

Vmax for laura= 5.319 × 2

V_max for laura = 10.638 m/s

Also, for healan;

Vmax = 3.745 × 3

V_max for Healan = 11.235 m/s

C) to find which sprinter is ahead at 6.00 s,

For Laura:

D = (½(5.319 × 2²)) + (2² × 10.638)

D_laura = 53.19 m

For Helen: D = (½(3.745 × 3²)) + (3 × 11.235) = 50.558 m

Difference = 53.19 - 50.558 = 2.632

Thus, Laura is ahead by 2.632 m

C) We are told that laura achieved max speed in 2 s while healan took 3 s. This means that when Laura had reached her maximum speed Healan was still accelerating. Thus;

From v_max = at

10.638 = (3.745)t

t = 10.638/3.745

t = 2.84 s

Distance travelled during this time is;

For Laura:

D = (½(5.319 × 2²) + (0.84)(10.638) = 19.574 m

Foe Healan:

D = (½(3.745 × 2.84²)) = 15.103 m

Difference = 19.574 - 15.103 = 4.471 m

Thus, Healan is 4.471 m behind laura

3 0

3 years ago

Identify the action/reaction force pair involved when you catch a ball?

hichkok12 [17]

The action force is that of the ball as if pushes into you hand. The reaction is the hand support force pushing back on the ball.

4 0

4 years ago

Block A has a mass of 0.5kg, and block B has a mass of 2kg. Block is is released at a height of 0.75 meters above B. The coeffic

VikaD [51]

Answer:

0.075 m

Explanation:

The picture of the problem is missing: find it in attachment.

At first, block A is released at a distance of

h = 0.75 m

above block B. According to the law of conservation of energy, its initial potential energy is converted into kinetic energy, so we can write:

$m_Agh=\frac{1}{2}m_Av_A^2$

where

$g=9.8 m/s^2$ is the acceleration due to gravity

$m_A=0.5 kg$ is the mass of the block

$v_A$ is the speed of the block A just before touching block B

Solving for the speed,

$v_A=\sqrt{2gh}=\sqrt{2(9.8)(0.75)}=3.83 m/s$

Then, block A collides with block B. The coefficient of restitution in the collision is given by:

$e=\frac{v'_B-v'_A}{v_A-v_B}$

where:

e = 0.7 is the coefficient of restitution in this case

$v_B'$ is the final velocity of block B

$v_A'$ is the final velocity of block A

$v_A=3.83 m/s$

$v_B=0$ is the initial velocity of block B

Solving,

$v_B'-v_A'=e(v_A-v_B)=0.7(3.83)=2.68 m/s$

Re-arranging it,

$v_A'=v_B'-2.68$ (1)

Also, the total momentum must be conserved, so we can write:

$m_A v_A + m_B v_B = m_A v'_A + m_B v'_B$

where

$m_B=2 kg$

And substituting (1) and all the other values,

$m_A v_A = m_A (v_B'-2.68) + m_B v_B'\\v_B' = \frac{m_A v_A +2.68 m_A}{m_A + m_B}=1.30 m/s$

This is the velocity of block B after the collision. Then, its kinetic energy is converted into elastic potential energy of the spring when it comes to rest, according to

$\frac{1}{2}m_B v_B'^2 = \frac{1}{2}kx^2$

where

k = 600 N/m is the spring constant

x is the compression of the spring

And solving for x,

$x=\sqrt{\frac{mv^2}{k}}=\sqrt{\frac{(2)(1.30)^2}{600}}=0.075 m$

5 0

3 years ago

A Van de Graaff generator is one of the original particle accelerators and can be used to accelerate charged particles like prot

Rzqust [24]

Answer:

595391.482946 m/s

$3.21875\times 10^{6}$

Explanation:

E = Energy = 1.85 keV

I = Current = 5.15 mA

e = Charge of electron = $1.6\times 10^{-19}\ C$

t = Time taken = 1 second

m = Mass of proton = $1.67\times 10^{-27}\ kg$

Velocity of proton is given by

$v=\sqrt{\dfrac{2E}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.85\times 10^3\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}}\\\Rightarrow v=595391.482946\ m/s$

The speed of the proton is 595391.482946 m/s

Current is given by

$I=\dfrac{\Delta Q}{t}\\\Rightarrow \Delta Q=It\\\Rightarrow \Delta Q=5.15\times 10^{-3}\times (1\ sec)\\\Rightarrow Q=5.15\times 10^{-3}\ C$

Number of protons is

$n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{5.15\times 10^{-3}}{1.6\times 10^{-19}}\\\Rightarrow n=3.21875\times 10^{6}\ protons$

The number of protons is $3.21875\times 10^{6}$

3 0

4 years ago

Which types of basketball injuries do you believe the warm-up could prevent? Explain

inn [45]

Answer:

pulling a muscle. putting too much strain on a muscle causing a tear.

Explanation:

Doing warm ups help your muscles adjust to the full extent of a basketball game. Warming up is like stretching, helps your muscles adjust before going full out on the court.

7 0

4 years ago