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Vikki [24]
3 years ago
13

How many L are in 1,500cm^3

s" id="TexFormula1" title="1500{cm}^{3} = \: ... \: liters" alt="1500{cm}^{3} = \: ... \: liters" align="absmiddle" class="latex-formula">
Chemistry
1 answer:
irga5000 [103]3 years ago
8 0
1.5 liters are in 1,500cm^3.
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How many moles of O2 should be supplied to burn 1.82 mol of C3H8 (propane) molecules In a camping stove?
pashok25 [27]

C3H8 + 5O2 ------> 3CO2 + 4H2O

from reaction 1 mol 5 mol

given 1.82 mol x mol


x=(1.82*5)/1 = 9.10 mol CO2

4 0
3 years ago
Plz help soon? I’m confused
nata0808 [166]
Hi,
I think the answer is metric.
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¿Cuáles son las formas alotrópicas del carbono (como se encuentra en la naturaleza)?
Mars2501 [29]

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Explanation:

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3 years ago
……….CO + ………H2 --> C8H18 + ……… H2O
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Answer:

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5 0
3 years ago
A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri
Helga [31]
The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
F= \frac{m* v^{2} }{r}
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if <span>F= \frac{m* v^{2} }{r}, then:
</span>    r= \frac{3* v^{2} }{F}
⇒ r =  \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }
⇒ r= \frac{1200*400*kg*m^{2}*s^{2}  }{6000kg*m/s^{2} }
⇒ r= \frac{480,000m}{6000}
⇒ r=80m


6 0
3 years ago
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