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rewona [7]
3 years ago
13

Which is a nonpolar molecule?

Chemistry
2 answers:
Nookie1986 [14]3 years ago
5 0
what is a non-polar molecule? Atoms are made of small particles. When atoms bond together to form molecules. They share or give electrons. If the electrons are shared equally by the atoms, then there is no resulting charge making the molecule nonpolar. Polar molecules are the complete opposite.
Kamila [148]3 years ago
3 0
A molecule may be nonpolar either when there is an equal sharing of electrons<span>between the two atoms</span>
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dusya [7]
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B is the temperature either released or absorbed.

The diagram shows that the reaction is exothermic based on the fact that the products energy is lower than the reactants. That is because energy (which is temperature in this case) is released during the process. If the reactants would have been lower than the products, the reaction would be endothermic.
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2 years ago
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What is pressure in relation to a gas?
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The pressure of a gas is the force that a gas exerts per unit area of the container.

Pressure is defined as force per unit area. Gas molecules are constantly colliding against the walls of the container. The pressure of the gas is the force the gas is exerting on its container.

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Learn more: brainly.com/question/11543614

7 0
2 years ago
Which statement describes the light reaction of photosynthesis?
cupoosta [38]

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3 years ago
Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang
Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

\Delta (H_{f})_{MnO_{2}} = -520.0 KJ/mole

\Delta (H_{f})_{Al_{2}O_{3}} = -1699.8 KJ/mole

The balanced chemical reaction is,

3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)

Formula used :

\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}

\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]

                        = (-3399.6) + (1560)

                        = -1839.6 KJ



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cestrela7 [59]

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