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jolli1 [7]
3 years ago
12

What are the three ways in which an atom can form bonds with other atoms?

Chemistry
1 answer:
Katena32 [7]3 years ago
5 0
The 3 ways are:-

1. Forming ionic bond by giving or taking electrons.

2. Forming Covalent bond by equal sharing of electrons.

3. Forming Co-ordinate bond by unequal sharing of electrons.
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1. A chemist prepares hydrogen fluoride by means of the following reaction:
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a) <em>Theoretical Yield of HF = 5.64 grams</em>

b) <em>Percentage Yield = 39%</em>

Explanation:

Reaction Given:

CaF2 + H2SO4 -> CaSO4 + 2HF

CaF2 = 11g

H2SO4 = Used in excess

HF = 2.2 g production = Actual Yield

So, Let's write down the molar masses:

Molar Mass of CaF2 = 78 g /mol

Molar Mass of HF = 20 g/mol

From the reaction, we can see the 1 mole of CaF2 gives the 2 moles of HF

i.e

a) Theoretical Yield of HF:

1 mole CaF2 = 2 moles HF

78 g CaF2 = 2 x 20 g of HF

78 g CaF2 = 40 g of HF

1 g CaF2 = 40g/78g of HF

And in the question it is given that chemist used 11 g of CaF2 so,

1 x 11 g of CaF2 = 11 x 40/78 g of HF

11 g of CaF2 = 440/78 g of HF

11 g of CaF2 = 5.64 g of HF

And this is the theoretical yield

<em>Theoretical Yield of HF = 5.64 grams</em>

b) Now, calculate the Percentage Yield of HF

<em>Percentage Yield = Actual Yield /Theoretical Yield x 100</em>

Percentage Yield = 2.2 g /5.64 g x 100

Percentage Yield = 39%

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2 years ago
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