Answer:
0.184 M
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HCl + NaOH —> NaCl + H2O
From the balanced equation above, the following data were obtained:
Mole ratio of the acid, HCl (nA) = 1
Mole ratio of the base, NaOH (nB) = 1
Next, the data obtained from the question. This includes:
Volume of the base, NaOH (Vb) = 31.7 mL Molarity of the base, NaOH (Mb) = 0.145 M
Volume of the acid, HCl (Va) = 25.0 mL
Molarity of the acid, HCl (Ma) =?
Finally, we shall determine the molarity of the acid (HCl) as shown below:
MaVa /MbVb = nA/nB
Ma × 25 / 0.145 × 31.7 = 1
Cross multiply
Ma × 25 = 0.145 × 31.7
Ma × 25 = 4.5965
Divide both side by 25
Ma = 4.5965 / 25
Ma = 0.184 M
Therefore, the molarity of the acid (HCl) is 0.184 M
