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devlian [24]
2 years ago
6

For each event stated below, indicate how the concentration of each species in the chemical equation then change to reach equili

brium. Click in the blue box below to toggle the relative change in concentration (up=increases, down=decreases leave the box blank for no change). 2CO(g)+O2(g) 2CO2 (g) increasing the concentration of CO increasing the concentration of CO2 decreasing the the volume of the system
Chemistry
1 answer:
xxTIMURxx [149]2 years ago
7 0

Answer:

Answers are in the explanation

Explanation:

It is possible to know the effect of change the conditions in an equilibirum based on LeChatelier's principle that says any change in conditions of a chemical system produce in the system an opposite response to counteract the initial change.

For the reaction:

2CO(g) + O₂(g) ⇄ 2CO₂(g)

<em>Increasing the concentration of CO: </em>The system will response producing more CO₂ counteracting the increasing of CO. CO concentration decreases, O₂ concentration decreases, CO₂ concentration increases

<em>Increasing the concentration of CO₂: </em>Here, the system response producing more CO and O₂ decreasing the concentration of CO₂

<em>Decreasing the volume of the system</em>: Here, the system will try to go in the direction that occupy less volume to counteract the increase of pressure because of decreasing of volume. In the left of the reaction there are three moles of gas and in the right there are just two. That means the system will produce more CO₂ decreasing, thus, concentration of CO and O₂.

I hope it helps!

<em />

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The temperature inside your freezer is 0 degrees Celsius. You place a balloon with an initial temperature of 30 degrees C and a
blsea [12.9K]

Answer:

V=0.68L

Explanation:

For this question we can use

V1/T1 = V2/T2

where

V1 (initial volume )= 0.75 L

T1 (initial temperature in Kelvin)= 303.15

V2( final volume)= ?

T2 (final temperature in Kelvin)= 273.15

Now we must rearrange the equation to make V2 the subject

V2= (V1/T1) ×T2

V2=(0.75/303.15) ×273.15

V2=0.67577931717

V2= 0.68L

4 0
3 years ago
Which of the following is a product of aerobic respiration?
sasho [114]

Answer:

The product of aerobic respiration is Carbon dioxide.

Explanation:

  • The process of breaking down glucose to produce energy and waste products is called respiration. Livings beings need respiration process to generate energy so  that they can survive.
  • The types of respiration are : Anaerobic and aerobic respiration.
  • Aerobic respiration takes place in presence of oxygen and produces large amount of energy.
  • The final product of aerobic respiration are carbon dioxide, water and 38 ATP of energy.
3 0
3 years ago
Read 2 more answers
Iodine chloride, ICl, can be made by the following reaction between iodine, I2, potassium iodate, KIO3, and hydrochloric acid.
Vadim26 [7]
The balanced chemical reaction is:

<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O 
</span>
We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.

28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2
6 0
3 years ago
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The element lanthanum has two stable isotopes, lanthanum-138 with an atomic mass of 137.9 AMU and lanthanum-139 with an atomic m
dmitriy555 [2]

Answer:

A. there is an isotope of lanthanum with an atomic mass of 138.9

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By knowing the different atomic masses of both Lanthanum atoms, we can not tell anything about their occurence in nature. Therefore, all the last three options are incorrect. Because, the atomic mass does not tell anything about the availability or natural abundance of an element.

Now, the isotopes of an element are those elements, which have same number of electrons and protons as the original element, but different number of neutrons. Therefore, they have same atomic number but, different atomic weight or atomic masses.

Hence, by looking at an elements having same atomic number, but different atomic masses, we can identify them as isotopes.

Thus, the correct option is:

<u>A. there is an isotope of lanthanum with an atomic mass of 138.9.</u>

7 0
3 years ago
HELPPPP PLEASEE!!!!!!!
OlgaM077 [116]

I think the answer is yes

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