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elena-s [515]
3 years ago
9

Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will

form, enter its empirical
formula in the last column.
solution A
solution B
Does a
precipitate form
when A and B
are mixed?
Oyes no
empirical
formula of
precipitate
х
X
x
5
?
copper(II) chloride
sodium sulfide
potassium sulfate
O yes no
lead(II) nitrate
ammonium bromide
sodium hydroxide
O yes no
Que

Chemistry
1 answer:
stiks02 [169]3 years ago
6 0

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules.  It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

  • In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
  • In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
  • In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g)  + NaBr(aq) + H2O(l), a precipitate is not formed here.

Learn more: brainly.com/question/11969651

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Consider 2 Al + 6 HCl → 2 AlCl3 + 3 H2 , the reaction of Al with HCl to produce hydrogen gas. What is the pressure of H2 if the
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Answer : The pressure of hydrogen gas is 8.96 atm.

Explanation :

The given balanced chemical reaction is:

2Al+6HCl\rightarrow 2AlCl_3+3H_2

From the balanced chemical reaction we conclude that,

As, 2 moles of Al react to give 3 moles of H_2 gas

So, 4.50 moles of Al react to give \frac{3}{2}\times 4.50=6.75 moles of H_2 gas

Now we have to calculate the moles of H_2 gas when percent yield is 75.4.

\text{The moles of }H_2=75.4\% \times 6.75=\frac{75.4}{100}\times 6.75=5.09moles

Now we have to calculate the pressure of H_2 gas.

Using ideal gas equation :

PV = nRT

where,

P = Pressure of hydrogen gas = ?

V = Volume of the hydrogen gas = 14.0 L

n = number of moles of hydrogen gas = 5.09 moles

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of hydrogen gas = 300 K

Putting values in above equation, we get:

P\times 14.0L=5.09mol\times 0.0821L.atm/mol.K\times 300K\\\\P=8.96atm

Therefore, the pressure of hydrogen gas is 8.96 atm.

3 0
2 years ago
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