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elena-s [515]
2 years ago
9

Complete the table below by deciding whether a precipitate forms when aqueous solutions A and B are mixed. If a precipitate will

form, enter its empirical
formula in the last column.
solution A
solution B
Does a
precipitate form
when A and B
are mixed?
Oyes no
empirical
formula of
precipitate
х
X
x
5
?
copper(II) chloride
sodium sulfide
potassium sulfate
O yes no
lead(II) nitrate
ammonium bromide
sodium hydroxide
O yes no
Que

Chemistry
1 answer:
stiks02 [169]2 years ago
6 0

The reaction between copper II chloride and sodium sulfide as well as lead II nitrate and potassium sulfate both produce precipitates.

The solubility of a substance in water is in accordance with the solubility rules.  It is possible that a solid product may be formed when two aqueous solutions are mixed together. That solid product is referred to as a precipitate.

Now, we will consider each reaction individually to decode whether or not a precipitate is possible.

  • In the first reaction, we have; CuCl2(aq) + Na2S(aq) ---->CuS(s) + 2NaCl(aq). A precipitate (CuS) is formed.
  • In the second reaction, Pb(NO3)2(aq) + 2KNO3(aq) ----> PbSO4(s) + KNO3(aq), a precipitate PbSO4 is formed
  • In the third reaction, NH4Br(aq) + NaOH(aq) ----->NH3(g)  + NaBr(aq) + H2O(l), a precipitate is not formed here.

Learn more: brainly.com/question/11969651

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Answer:

No

Explanation:

In ideal solutions, the interactions between solute - solvent are approximately the same as those of solute - solute and solvent - solvent, that is the interactions are to be practically indistintiguishable after disolution.

The moment we have a release of energy (the solution feels warm) we are to conclude that there are strong interactions between the water and methanol molecules so we would expect the solution to be non ideal.

The reason for the interactions is the presence of hydrogen bonds between methanol and water.

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