<span>What type of mixture is it:
Colloid </span>
Scientific would be the word to fill in the blank
The given example is a chemical reaction.
The contents (separated as reactants and products) :

The written reaction is :

<em>I hope it helped you solve the problem.</em>
<em>Good luck on your studies!</em>
Answer:

Explanation:
Hello there!
In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

Which is also balanced as the number of atoms of all the elements is the same at both sides.
Best regards!
It’s ionic bond based on electrons gain/loss.