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Musya8 [376]
3 years ago
5

You need 455 ml of a 75% alcohol solution. on hand, you have a 25% alcohol mixture. you also have a 90% alcohol mixture. how muc

h of each mixture will you need to add to obtain the desired solution?
Chemistry
1 answer:
marishachu [46]3 years ago
8 0
X ml - <span>25% alcohol mixture
y ml - </span><span>90% alcohol mixture

x+y = 455 

0.25x ml alcohol in </span>x ml of  25% alcohol mixture
0.9y ml alcohol in y ml of  90% alcohol mixture
0.75*455= 341.25 ml alcohol in 455 ml of  75% alcohol mixture

0.25x+0.9y=341.25 

System of equations:

x+y = 455 /*(-0.25) ------> -0.25x-0.25y = -0.25*455 
0.25x+0.9y=341.25

-0.25x-0.25y=-113.75
0.25x+0.9y=341.25    Add both equations

0.25x+0.9y-0.25x-0.25y=341.25-113.75
0.65y =227.5
y=227.5/0.65 = 350 ml  of  90% alcohol mixture

x+y=455
x+355=455
x=100 ml of  25% alcohol mixture

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1. Calculate the quantity of glucose needed to prepare (a) 250 mL of a 100 mM of
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a. mass of glucose required = 4.50 g

b. mass of glucose required = 0.05 g

c. mass of glucose required = 25g

Explanation:

1a. molar mass of glucose = 180.156 g/mol

volume of solution = 250 mL or 250 mL * 1 L/1000 mL = 0.25 L

concentration of solution = 100 mM or 100mM * 1 M/1000 mM = 0.10 M

amount in moles = mass/ molar mass = concentration * volume

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mass = 0.10 * 0.25 * 180.156

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