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RSB [31]
3 years ago
8

A 0.0200 M NaCl solution was formed when 38.0 grams of NaCl was dissolved in enough water. What was the total volume of the solu

tion formed?
Chemistry
2 answers:
Ksenya-84 [330]3 years ago
8 0

<u>Answer:</u> The volume of the solution formed will be 32.5 L.

<u>Explanation:</u>

Molarity is defined as the amount of solute present in 1 L of solution. The equation used to determine molarity of the solution follows:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of the solution = 0.02 mol/L

Mass of NaCl = 38 grams

Molar mass of NaCl = 58.5 g/mol

Putting values in above equation, we get:

0.02mol=\frac{38g}{58.5g/mol\times V_s}\\\\\text{Volume of the soltion}=32.5L

Hence, the volume of the solution formed will be 32.5 L.

pashok25 [27]3 years ago
4 0

First calculate the no of moles, that is 38 grams divided by molar mass which is 58.43 g/mol. The no of moles is 0.65 moles. Concentration= no of moles divided by volume in litre. From the above formula, volume= no of moles divided by concentration. So to get the total volume 0.65 moles divided by 0.02M (mol/L) which gives 32.5 L.

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A solution of phosphoric acid was made by dissolving 10.8 g of H3PO4 in 133.00 mL of water. The resulting volume was 137 mL. Cal
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Answer:

Density is: 1.05 g/ml

Mole fraction solute: 0.015

Mole fraction solvent:  0.095

Molarity: 0.80 M

Molality: 0.82 m

Explanation:

A typical excersise of solution.

It is more confortable to make a table for this.

                |   masss  |  volume  |  mol

solute       |                |                |          

solvent     |                |                |  

solution    |                |                |

Let's complete, what we have.

                 |   masss  |  volume  |  mol

solute       |  10.8g     |                |          

solvent     |                |  133 mL   |  

solution    |                |  137 mL    |

We can first, know how many moles are 10.8 g

Molar Mass H3PO4 = 97.99 g/mol

Mass / Molar mass = mol

10.8 g / 97.99 g/m = 0.110 mol

Density of water is 1 g/ml (it is a very knowly value)

From this data, we can know water mass, solvent.

Density = mass / volume

1 g/ml = mass / 133 mL

Mass = 133 g

We can also have the moles, by the molar mass of water 18 g/m

133 g / 18 g/m = 7.39 mol

                 |   masss  |  volume  |  mol

solute       |   10.8g     |                |   0.110 mol      

solvent     |   133g      |  133 mL   |  7.39 mol

solution    |   143.8g   |  137 mL   | 7.50 mol

Mass of solution will be solute mass + solvent mass

Moles of solution will be solute moles + solvent moles

Now we can calculate everything.

Molarity means mol of solute in 1 L of solution. (mol/L)

We have to convert 137 mL in L (/1000)

0.137L so → 0.110 m / 0.137L = 0.80 M

Molality means mol of solute in 1kg of solvent.

We have to convert 133g in kg (/1000)

0.133 kg so → 0.110 m/0.133 kg = 0.82 m

Density is mass / volume

Solution density will be solution mass / solution volume

143.8 g/137 mL = 1.05 g/m

Molar fraction is : solute moles / total moles  or  solvent moles/total moles.

You can also (x 100%) to have a percent of them.

Remember sum of molar fraction = 1

Molar fraction of solute = 0.110 mol / 7.50mol = 0.015

Molar fraction of solvent = 7.39 mol / 7.50 mol = 0.985

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Answer:

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So lowest boiling point is 0.13 m Mn(NO₃)₂.

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Third lowest boiling point is 0.17 m CrSO4

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b .  1

c . 2

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A student is given two 10g samples, each a mixture of only nacl(s) and kcl(s) but in different proportions. Which of the followi
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Answer:

a

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