Determine if the following relations are functions. If they are functions, also state the domain and range.
2 answers:
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Hi there!
Since you haven't given any numbers, I'll explain what you can do to figure this problem out. First, determine what side you have in relation to the angle (is it adjacent to the angle, it is opposite the angle, is it the hypotenuse?). Then, determine which trigonometry function to use (Sine = opposite/hypotenuse, Cosine = adjacent/hypotenuse, Tangent = opposite/adjacent). Check out the image below if you're confused. Anyway, you can use trigonometry to find the missing side of a triangle when only given angles and a side. All you have to do is plug in the numbers given and solve. (In the image, the O with a line through it represents the angle measurement that will be plugged in there.)
Hope this helps!! :)
If you're still confused or would like help solving a trigonometry problem, feel free to send me a message!
Since you haven't given any numbers, I'll explain what you can do to figure this problem out. First, determine what side you have in relation to the angle (is it adjacent to the angle, it is opposite the angle, is it the hypotenuse?). Then, determine which trigonometry function to use (Sine = opposite/hypotenuse, Cosine = adjacent/hypotenuse, Tangent = opposite/adjacent). Check out the image below if you're confused. Anyway, you can use trigonometry to find the missing side of a triangle when only given angles and a side. All you have to do is plug in the numbers given and solve. (In the image, the O with a line through it represents the angle measurement that will be plugged in there.)
Hope this helps!! :)
If you're still confused or would like help solving a trigonometry problem, feel free to send me a message!
Answer:
y = csc(x - 3/4)
Step-by-step explanation:
I forgot how to answer questions like these. I went ahead and tried re-learning this to answer this.
So, the first step is to recognize that this graph can only be the reciprocal function of sin or cosine. I will think of sine.
y = sin(x)
Look at where the x-coordinate of the sin is. (-3/4PI). This is going to be the c value. { y = asin(x-c) }
y = sin(x - 3/4)
Now, what is the a value? or amplitude? Well, it's just 1.. and the simplest explanation is just to look at my picture.
Now, if we were to graph this, we would end up with the correct x and y values, but the shape is wrong, and the easiest way to fix this is to just take the recpriocal of the sine function.
y = csc(x - 3/4)
Thank you for this question, I re-learned something I forgot back in pre-calc haha.
