<u>Given</u>:
Line m is parallel to line n.
The measure of ∠1 is (4x + 15)°
The measure of ∠2 is (9x + 35)°
We need to determine the measure of ∠1
<u>Value of x:</u>
From the figure, it is obvious that ∠1 and ∠2 are linear pairs.
Thus, we have;

Substituting the measures of ∠1 and ∠2, we get;




Thus, the value of x is 10.
<u>Measure of ∠1:</u>
The measure of ∠1 can be determined by substituting x = 10 in the measure of ∠1
Thus, we have;



Thus, the measure of ∠1 is 55°
Answer: 12
Step-by-step explanation:
There is no graph I’m sorry I can’t help
There’s probably an easier way to do it like with the equation to find the area of a trapezoid but i did it this way bc it’s easier for me
i split the trapezoid into a triangle and a square
with the pythagorean theorem i found the missing side length to find the area of the square (length X width)
then found the area of the triangle (base X height divided by 2)
THE ANSWER IS 68.9 CM
Answer:
(6x + 5)(7x² - 6)
Step-by-step explanation:
Factor the first/second and third/fourth term
42x³ + 35x² - 36x - 30
= 7x²(6x + 5) - 6(6x + 5) ← factor out (6x + 5) from each term
= (6x + 5)(7x² - 6)