Step One
How far as the slower train traveled in 3 hours?
<u>Formula</u>
d = r* t
r = 24 mph
t = 3 hours
d = ??
d = 24 * 3
d = 72 miles.
Step two
Start the clock at noon when the faster train begins to move. How much time will elapse before the fast train catches the slow one?
d = 60*t fast train
d = 24*t + 72 slow train The distances are the same so they can be equated..
Step Three
Solve the equation
60t = 24t + 72 Subtract 24t from both sides.
60t - 24t = 72
36t = 72 Divide by 48
t = 72 / 36
t = 2 hours.
How far does the fast train go in 2 hours?
d = r * t
r = 60 mph
t = 2 hours.
d = 60 * 2
d = 120 miles
How far does the slow train go in 2 hours.
r = 24 mph
t = 2 hours
d = 24 * 2
d = 48 miles
But the slow train started out 72 miles ahead of the fast train. It's distance from Boston is 48 + 72 = 120 miles.
Answer: Both trains will meet 120 miles away from Boston <<<<< Answer
5 x 4 = 20
7 x 4 = 28
5:7 = 20:28
When you multiply both by 4, they equal the outcome on their side of the function, making them equivalent
(Sorry if function isn't the right word)
Answer:
sec(θ) = -5/2
Step-by-step explanation:
It can be helpful to draw a triangle with sides that produce the given ratio. See the attachment. Then the third side of the triangle can be found using the Pythagorean theorem, if necessary. Finally, the ratio for the desired trig function can be determined.
sec = hypotenuse/adjacent
sec(θ) = 5/-2 = -5/2
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If you don't want to do that, or if you have various trig identities memorized, you can use the appropriate trig identity.
sin² + cos² = 1
so ...
sec² = 1/cos² = 1/(1 -sin²)
sec = 1/√(1 -sin²)
Since the tangent is positive, this is a third-quadrant angle. The secant will be negative.
sec(θ) = -1/√(1 -(21/25)) = -√(25/4) . . . . . filling in the given value for sin(θ)
sec(θ) = -5/2
It is 4 as you can see every y in the table is 4 time bigger than x.
Answer: 125.66
Step-by-step explanation: my explanation is i searched it
