Answer:
<u>According </u><u>to</u><u> the</u><u> </u><u>Given</u><u> Statement</u><u> </u>
Canon fires directly upwarda at 150m/s ( Initial speed, u )
Acceleration due to gravity is 10m/s²
Since Cannon ball reach it maximum height so its final velocity v will be 0 m/s .
Using Kinematic Equation
On substituting the value we get
➥ 0 = 150 + 10 × t
➥ 150 = 10 × t
➥ 150/10 = t
➥ 15 s = t
So, it will take 15 seconds .
Answer:
The current in third branch is 11 A.
Explanation:
incoming current in one branch = 18 A
outgoing current in the other branch = 7 A
let the current in the third branch is i.
According to the Kirchoff's fist law in electricity
incoming current = out going current
18 = 7 + i
i = 11 A
The current in third branch is 11 A.
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Answer:
(orbital speed of the satellite) V₀ = 3.818 km
Time (t) = 4.5 × 10⁴s
Explanation:
Given that:
The radius of the Earth is 6.37 × 10⁶ m; &
the acceleration of gravity at the satellite’s altitude is 0.532655 m/s
We can calculate the orbital speed of the satellite by using the formula:
Orbital Speed (V₀) = √(r × g)
radius of the orbit (r) = 21000 km + 6.37 × 10⁶ m
= (2.1 × 10⁷ + 6.37 × 10⁶) m
= 27370000
= 2.737 × 10⁷m
Orbital Speed (V₀) = √(r × g)
Orbital Speed (V₀) = √(2.737 × 10⁷ × 0.532655 )
= 3818.215
= 3.818 × 10³
= 3.818 Km
To find the time it takes to complete one orbit around the Earth; we use the formula:
Time (t) = 2 π ×
= 2 × 3.14 ×
= 45019.28
= 4.5 × 10 ⁴ s
Answer:
705.6 m
Explanation:
time, t = 12 sends
initial velocity, u = 0
Acceleration due to gravity, g = - 9.8 m/s^2
As the object is falling freely so the initial velocity is zero.
Let the distance traveled by the body is h in time t = 12 s.
Use second equation of motion
Ad the distance is downwards so take it as negative
So,
h = 705.6 m
Thus, the distance traveled in 12 second is 705.6 m