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Ipatiy [6.2K]
1 year ago
8

If a substance has a half-life of 45 min, how many minutes will it take for 220 g of the substance to be depleted to 1.00 g?.

Physics
1 answer:
AnnZ [28]1 year ago
4 0

The time taken for the substance to decay to 1 g of its original mass is 350 mins.

<h3>What is half life?</h3>

The half life of a radioactive element is the time taken for the half of the element to decay to half of its original size.

N = N₀(¹/₂)^t/h

where;

  • N is the remaining mass
  • N₀ is the original mass
  • h is half life
  • t is time

1 = 220(¹/₂)^t/h

1/220 = (¹/₂)^t/h

log(1/220) = log(¹/₂)^t/h

log(1/220) = t/h [log(¹/₂)]

-2.342 = t/h (-0.301)

7.78 = t/h

7.78 x h = t

7.78 x 45 min = t

350 mins = t

Thus, the time taken for the substance to decay to 1 g of its original mass is 350 mins.

Learn more about half life here: brainly.com/question/2320811

#SPJ1

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3 years ago
If a mass of 76 kg acts downward 0.38 m from the axis of rotation on one end of a board and another force of 129 N also acts dow
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6 0
2 years ago
A 9.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi
m_a_m_a [10]

Answer:

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Explanation:

<em>Let Recall that,</em>

<em> The power formula is:  </em>

<em>   P = E²/R  </em>

Let A = the magnetic field  

<em>Let L = length of wire  = 9.00cm = 0.09 m  </em>

let  R = resistance of wire  = 0.320 Ω

let v =  velocity of the wire = 4 m/s  

<em>Let E = across the wire voltage </em>

Let P = the power of the wire = 4.3 W  

To Solve  for E:  

<em>The formula of E = √PR  </em>

The Voltage from  a magnetic field is given as,

E = vAL  

We therefore Use E = E

√PR = vAL  

to solve  for A,

A= √PR/vL  

BA= √4.3(0.32)/(4)(.09)  -=0.173

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Let F  be  the pulling force  

Let I  be the current in the wire  

P = I²R  

<em>I = √P/R  </em>

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F = √P/RAL  

F = √4.3/.32(0.173)(.09)  

<em>F = 0.45N</em>

5 0
3 years ago
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