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Ipatiy [6.2K]
1 year ago
8

If a substance has a half-life of 45 min, how many minutes will it take for 220 g of the substance to be depleted to 1.00 g?.

Physics
1 answer:
AnnZ [28]1 year ago
4 0

The time taken for the substance to decay to 1 g of its original mass is 350 mins.

<h3>What is half life?</h3>

The half life of a radioactive element is the time taken for the half of the element to decay to half of its original size.

N = N₀(¹/₂)^t/h

where;

  • N is the remaining mass
  • N₀ is the original mass
  • h is half life
  • t is time

1 = 220(¹/₂)^t/h

1/220 = (¹/₂)^t/h

log(1/220) = log(¹/₂)^t/h

log(1/220) = t/h [log(¹/₂)]

-2.342 = t/h (-0.301)

7.78 = t/h

7.78 x h = t

7.78 x 45 min = t

350 mins = t

Thus, the time taken for the substance to decay to 1 g of its original mass is 350 mins.

Learn more about half life here: brainly.com/question/2320811

#SPJ1

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Calculate the molarity of a 10. 0% cacl₂ solution. The density of the solution is 1. 0835 g/cm³.
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The molarity of 10% CaCl2 is 0.9%

concentration of the given salt CaCl₂ = 10%

Density of a solution = 1.0835 g/cm³

Volume = m / d

= 100 / 1.0835

= 92.29 litres

Density = mass / volume

1.0835 × 92.29 = mass

mass = 99.99 gram

Thus the molarity can be calculated by = moles of solute / volume of solution multiplied by 100

= 0.9008/ 92.29 X 100 %

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A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn
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Answer:

a. 16 s b. -1.866 kJ

Explanation:

a. Since the initial rotational speed ω₀= 3313 rev/min = 3313/60 × 2π rad/s = 346.94 rad/s. Its rotational speed becomes ω₁ = 0.75ω₀ in time t = 4 s.

We find it rotational acceleration using α = (ω₁ - ω₀)/t = (0.75ω₀ - ω₀)/t = ω₀(0.75 - 1)/t = -0.25ω₀/t = (-0.25 × 346.94 rad/s)/4 s = -21.68 rad/s².

Since the turntable stops at ω = 0, the time it takes to stop is gotten from

ω = ω₀ + αt and t = (ω - ω₀)/α = (0 - 346.94 rad/s)/-21.68 rad/s² = (-346.94/-21.68) s = 16 s.

So it takes the turntable 16 s to stop.

b. The workdone by the turntable to stop W equals its rotational kinetic energy change.

So, W = 1/2Iω² - 1/2Iω₀² = 1/2 × 0.031 kgm² × 0² - 1/2 × 0.031 kgm² × (346.94 rad/s)² = 0 - 1865.7 J = -1865.7 J = -1.8657 kJ ≅ -1.866 kJ

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