Answer:
32 turns
Explanation:
From the expression for the induced emf,
E = (N)(B)(A) w
E = emf = 24 V
N = number of turns = ?
B = magnetic field strength = 0.10 T
A = Cross sectional Area of the loop = 100 cm² = 0.01 m²
w = Angular speed = (2πf) = (2π × 120) = 754.3 rad/s
24 = N (0.1)(0.01)(754.3)
N = (24/0.7543)
N = 31.8 ≈ 32 turns.
Hope this Helps!!!
Answer:
Explanation:
a)
Ff = μmgcosθ
Ff = 0.28(1600)(9.8)cos(-84)
Ff = 458.9217...
Ff = 460 N
b) ignoring the curves required at top and bottom which change the friction force significantly, especially at the bottom where centripetal acceleration will greatly increase normal forces and thus friction force.
W = Ffd
W = 458.9217(-49.4/sin(-84)
W = 22,795.6119...
W = 23 kJ
c) same assumptions as part b
The change in potential energy minus the work of friction will be kinetic energy.
KE = PE - W
½mv² = mgh - (μmgcosθ)d
v² = 2(gh - (μgcosθ)(h/sinθ))
v = √(2gh(1 - μcotθ))
v = √(2(9.8)(49.4)(1 - 0.28cot84))
v = 30.6552...
v = 31 m/s
D, electron, the nucleus is not a single particle to begin with, the proton has a positive charge, a neutron has a neutral charge or no charge, and an electron has a negative charge
Will this one work?...................
