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just olya [345]
2 years ago
9

wo bullets are fired at the same time with the same kinetic energy. If one bullet has twice the mass of the other, which has the

greater speed and by what factor? Which can do the most work?T
Physics
1 answer:
marishachu [46]2 years ago
5 0

Answer:

velocity of other bullet will be v_2^2=\sqrt{2}v_1

As kinetic energy of both bullet are same so they will do same amount of work

Explanation:

We have given that two bullets are fired with same kinetic energy

So KE_1=KE_2

Let the mass of bullet 1 is m_1 and mass of bullet 2 is m_2

And their velocity are v_1 and v_2

According to question m_1=2m_2

So \frac{1}{2}\times 2m_2\times v_1^2=\frac{1}{2}\times m_2\times v_2^2

v_2^2=2v_1^2

v_2^2=\sqrt{2}v_1

So velocity of other bullet will be v_2^2=\sqrt{2}v_1

As kinetic energy of both bullet are same so they will do same amount of work

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Stellar nurseries, such as the orion nebula, contain hundreds or more fragmenting and contracting regions, as well as many proto
Natasha_Volkova [10]

The hydrogen fusion process will begin after the protostar reaches a temperature of 10 million degrees kelvin, and it will then turn into a stable star.

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3 0
1 year ago
If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?
andreyandreev [35.5K]

Answer:

v = -6m/s

Explanation:

x=4-12t+3t^2

\frac{dx}{dt}=-12+6t

For t = 1:

\frac{dx}{dt}=-6

3 0
3 years ago
Find the acceleration of a car with a mass of 1,200 kg and a force of 11,000 N.<br> Please help
netineya [11]

Answer:

9.17 m/s^2

Explanation:

Formula for force is given by

F = m*a

where F is the force in newton

m is the mass of body in KG

and

a is the acceleration of body on m/s^2

_______________________________________________

Given

F = 11,000

mass = 1,200 Kg

we have to find value of acceleration

using

F = m*a

11,000 = 1200*a

=> a = 11,000 /1200 = 9.17

Thus, the acceleration of a car is 9.17 meter per second square

5 0
2 years ago
A solenoid that is 78.8 cm long has a cross-sectional area of 15.9 cm2. There are 914 turns of wire carrying a current of 8.25 A
Harlamova29_29 [7]

Answer:

(a) Energy density will be equal to 57.31J/m^3

(b) Total energy will be equal to 0.0718 J

Explanation:

It is given that length of solenoid l = 78.8 cm = 0.788 m

Cross sectional area A=15.9cm^2=15.9\times 10^{-4}m^2

Number of turns of the wire N = 914

Current in the solenoid i = 8.25 A

Inductance of the wire is equal to L=\frac{\mu _0N^2A}{l}=\frac{4\pi \times 10^{-7}\times 914^2\times 15.9\times 10^{-4}}{0.788}=2.117\times 10^{-3}H

(b) Total energy stored in magnetic field U=\frac{1}{2}Li^2=\frac{1}{2}\times 2.11\times 10^{-3}\times 8.25^2=0.0718J

(a) Energy density will be equal to

U_b=\frac{0.0718}{15.9\times 10^{-4}\times 0.788}=57.31J/m^3

7 0
2 years ago
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