Answer:
Answer below :)
Explanation:
<u>SIZE OF THEODOLITE:</u> A theodolite is designated by diameter of the graduated circle on the lower plate. The common sizes are 8 cm to 12 cm while<em> 14 cm</em> to <em>25 cm</em> instrument are used for triangulation work.
Answer:
The correct option is;
Fluid power systems are much more efficient with regards to energy costs and overall cost savings
Explanation:
The option that will provide a valid reason for the larger proportion of the consumers to change to the fluid power trucks from the diesel powered trucks is the possibility of increased efficiency in the cost of energy, and the cost savings to be made from making the switch to the fluid power trucks, due to the lower input required and the faster rate at which the consumer budget will be rebalanced leading to increased return on investment and improved rate of return.
Answer:
<em>Technician B says that a ratchet is used to loosen fasteners that are very tight.</em>
Explanation:
A ratchet is a common wrench device with a fastener component. A ratchet wrench is an essential tool that is used to fasten or loosen nuts and bolts.
Answer:
25 V
Explanation:
It is convenient to use Kirchoff's current law (KCL), which tells you the sum of currents into a node is zero. The node of interest is the top left node.
The currents into it are ...
20 mA + (-5 -Vo)/(2kΩ) -(Vo/(5kΩ)) = 0
20 mA -2.5 mA = Vo(1/(2kΩ) +1/(5kΩ)) . . . . add the opposite of Vo terms
(17.5 mA)(10/7 kΩ) = Vo = 25 . . . volts . . . . divide by the coefficient of Vo
_____
You will notice that the equation resolves to what you would get if you drew the Norton equivalent of the voltage source with its 2k impedance. You have two current sources, one of +20 mA, and one of -2.5 mA supplying current to a load of 2k║5k = (10/7)kΩ. KCL tells you the total current into the node is equal to the current through that load (out of the node).
Answer:
void bubble_sort( int A[ ], int n ) {
int temp;
for(int k = 0; k< n-1; k++) {
// (n-k-1) to ignore comparisons of already compared iterations
for(int i = 0; i < n-k-1; i++) {
if(A[ i ] > A[ i+1] ) {
// swapping occurs here
temp = A[ i ];
A[ i ] = A[ i+1 ];
A[ i + 1] = temp ;
}
}
}
}
