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dsp73
3 years ago
14

For a 68 wt% Zn-32 wt% Cu alloy, make schematic sketches of the microstructure that would be observed for conditions of very slo

w cooling at the following temperatures: 1000C (1830F), 760C (1400F), 600C (1110F), and 400C (750F). Label all phases and indicate their approximate compositions.

Engineering
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

-At 1000°C, liquid phase at 68 wt% Zn

-At 760°C, liquid+γ phase, liquid at 74 wt% and 66 wt% γ phase

-At 600°C, γ phase

-At 400°C, γ phase

Explanation:

The phase diagram will be used for the combination of the copper-zinc alloy, first 68% by weight of Zn will be located on the axis corresponding to the composition. Draw a vertical line upwards and go through the temperatures given by the exercise 1000, 760, 600 and 400 ° C. Later you have to know the phases for each of the temperatures. Draw a horizontal line within each phase and look at the adjacent phases and the composition of the alloy. For each of the temperatures, the phases are in response and the drawings are attached to the image.

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If something is 50fficient, how many joules of wasted energy will there be if 750j of energy is put in?’
Sedbober [7]

Efficiency is the minimum use of energy to accomplish the task. The wasted energy will be 375 J when 750 J of energy is given.

<h3>What is wasted energy?</h3>

Wasted energy is energy that is not useful when the transformation in the system occurs.

Total energy = 750 J

The efficiency of the system = 50 %

Output work (OW) is calculated as:

Efficiency = output work ÷ input work × 100%

750 × 50 = 100 OW

OW = 375 J

Wasted energy = Total energy - output work

= 750 - 375

= 375 J

Therefore, the machine is 50 % inefficient and has wasted energy of 375 J.

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2 years ago
In remote areas, your gps devices may lose reception. It’s a good idea to have a
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4 0
3 years ago
Read 2 more answers
A quantity of water within a piston-cylinder assembly executes a Carnot power cycle. During isothermal expansion, the water is h
Harman [31]

Answer:

  Answer with Explanation is in the following attachments.

                     

Explanation:

7 0
3 years ago
The size of Carvins Cove water reservoir is 3.2 billion gallons. Approximately, 11 cfs of water is continuous withdrawn from thi
Zolol [24]

Answer:

471 days

Explanation:

Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons

As,  

1 gallon = 0.133 cubic feet (cf)

Therefore,  

Capacity of Carvins Cove water reservoir in cf  = 3.2 x 10˄9 x 0.133

                                                                         = 4.28 x 10˄8

 

Applying Mass balance i.e

Accumulation = Mass In - Mass out   (Eq. 01)

Here  

Mass In = 0.5 cfs

Mass out = 11 cfs

Putting values in (Eq. 01)

Accumulation  = 0.5 - 11

                         = - 10.5 cfs

 

Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.

Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600

                                                                                       = 37,800

 

Converting depletion of reservoir in cubic feet per day = 37, 800 x 24

                                                                                         = 907,200  

 

i.e. 907,200 cubic feet volume is being depleted in days = 1 day

1 cubic feet volume is being depleted in days = 1/907,200 day

4.28 x 10˄8 cubic feet volume will deplete in days  = (4.28 x 10˄8) x                    1/907,200

                                                                                 = 471 Days.

 

Hence in case of continuous drought reservoir will last for 471 days before dry-up.

8 0
3 years ago
Explain by Research how a basic generator works ? using diagram<br>​
natulia [17]
Correcto no se muy bien de que se trata el tema porque está en inglés.
Sorry
8 0
3 years ago
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