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2 years ago

14

if you want to withdraw $10000 at the end of two years and $35000 at the end of four years, how much should you deposit now into

an account that pays 9% interest compounded annually?

1 answer:

Katen [24]2 years ago

3 0

Answer:

490000 dollars

Explanation:

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Air at 38°C and 97% relative humidity is to be cooled to 14°C and fed into a plant area at a rate of 510m3/min. (a) Calculate th

Katarina [22]

To develop the problem it is necessary to apply the concepts related to the ideal gas law, mass flow rate and total enthalpy.

The gas ideal law is given as,

$PV=mRT$

Where,

P = Pressure

V = Volume

m = mass

R = Gas Constant

T = Temperature

Our data are given by

$T_1 = 38\°C$

$T_2 = 14\°C$

$\eta = 97\%$

$\dot{v} = 510m^3/kg$

Note that the pressure to 38°C is 0.06626 bar

PART A) Using the ideal gas equation to calculate the mass flow,

$PV = mRT$

$\dot{m} = \frac{PV}{RT}$

$\dot{m} = \frac{0.6626*10^{5}*510}{287*311}$

$\dot{m} = 37.85kg/min$

Therfore the mass flow rate at which water condenses, then

$\eta = \frac{\dot{m_v}}{\dot{m}}$

Re-arrange to find $\dot{m_v}$

$\dot{m_v} = \eta*\dot{m}$

$\dot{m_v} = 0.97*37.85$

$\dot{m_v} = 36.72 kg/min$

PART B) Enthalpy is given by definition as,

$H= H_a +H_v$

Where,

$H_a$ = Enthalpy of dry air

$H_v$ = Enthalpy of water vapor

Replacing with our values we have that

$H=m*0.0291(38-25)+2500m_v$

$H = 37.85*0.0291(38-25)-2500*36.72$

$H = 91814.318kJ/min$

In the conversion system 1 ton is equal to 210kJ / min

$H = 91814.318kJ/min(\frac{1ton}{210kJ/min})$

$H = 437.2tons$

The cooling requeriment in tons of cooling is 437.2.

3 0

3 years ago

A model of a submarine, 1:15 scale, is to be tested at 180 ft/s in a wind tunnel with standard sea-level air, while theprototype

ella [17]

Answer:

Explanation:

Given

scale i.e. $L_r=1:15$

Using Reynolds number similarity

$(Re)_m=(Re)_p$

$(\frac{Vl}{\nu })_m=(\frac{Vl}{\nu })_p$

Properties of air

$\nu _{air}=1.57\times 10^{-4} ft/s$

Properties of sea water

$\nu _{sea}=1.26\times 10^{-5} ft/s$

$\left ( \frac{V_ml_M}{\nu _m}\right )=\left ( \frac{V_pl_p}{\nu _p}\right )$

$V_p=V_m\left ( \frac{l_m}{l_p}\right )\left ( \frac{\nu _p}{\nu _m}\right )$

$V_p=180\times \frac{1}{15}\times \frac{1.26\times 10^{-5}}{1.57\times 10^{-4}}$

$V_p=0.963\ ft/s$

8 0

3 years ago

In the combination of resistors above, consider the 1.50 µΩ and 0.75 µΩ. How can you classify the connection between these two r

Airida [17]

Answer: they are connected in series.

Explanation:

3 0

4 years ago

Scientists learn more about the natural world through investigation. This involves identifying a problem, researching related in

mars1129 [50]

Answer:

This shows that the technological designs are similar to the scientific investigation processes.

Explanation:

Scientists carry out scientific investigations and discoveries. They learn from their environment by investigating the natural world. The scientist investigates by problem identification, research the related information, designing and conceptualizing, investigating and analyzing the results and deriving out conclusions.

Similarly the engineers follow the same step and provide solutions to the problems of the society through their products and technological designs. The engineers first identify the need of the product, design and implement the design to provide solution and then evaluate the solution. These are the similar steps that an engineer follow in a technological design of a product or a solution.

3 0

3 years ago

What is the step in which you are testing your hypothesis

jonny [76]

Answer:

Step 1: State your null and alternate hypothesis. ...

Step 2: Collect data. ...

Step 3: Perform a statistical test. ...

Step 4: Decide whether the null hypothesis is supported or refuted. ...

Step 5: Present your findings.

8 0

3 years ago