Answer: 9x^2 - 6x + 8
Step-by-step explanation:
(9x^2 - 2x + 7) - (4x - 1) Subtract like terms
The term 9x^2 doesn't have any other term so it will stay alone.
-2x - 4x = - 6x
7 - (-1) = 8
Put them together to get 9x^2 - 6x + 8
The correct answer is B. Multiply input number by 4
Answer:
Kindly check explanation
Step-by-step explanation:
Given the dimension of the dog pen = 30 ft by 40 ft.
Using the knowledge of geometry, that know that a rectangle has been built, the area of the pen should be :
Area of rectangle = Length * width
Area = 40 * 30
Area = 1200 ft²
Perimeter of rectangle = 2(Length + width)
Perimeter = 2(40 + 30)
Perimeter = 2(70)
Perimeter = 140 feets
Hence, area of the pen should be 1200 ft² and its perimeter or fencing should measure 140 feets
15 bags you will only use 14 full bags and use some of the 15th bag
Answer:
a. We reject the null hypothesis at the significance level of 0.05
b. The p-value is zero for practical applications
c. (-0.0225, -0.0375)
Step-by-step explanation:
Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.
Then we have 
, 
, 
and 
, 
, 
. The pooled estimate is given by
a. We want to test 
vs 
(two-tailed alternative).
The test statistic is 
and the observed value is 
. T has a Student's t distribution with 20 + 25 - 2 = 43 df.
The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value 
falls inside RR, we reject the null hypothesis at the significance level of 0.05
b. The p-value for this test is given by 
0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.
c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)
, i.e.,
where 
is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So
, i.e.,
(-0.0225, -0.0375)
