Answer:
the answer is 6
Step-by-step explanation:
For this case we have the following function:
Where,
g: number of gallons of gas
M (g): number of miles that Danny's truck travels
We know that the maximum capacity is 20 gallons of gas.
Therefore, the maximum distance the truck can travel is given by:
Thus, the domain of the function is:
![0 \leq g \leq 20](https://tex.z-dn.net/?f=%200%20%5Cleq%20g%20%5Cleq%2020%20)
The range of the function is:
Answer:
A domain and range that are reasonable for the function are:
D. D: 0 ≤ g ≤ 20
R: 0 ≤ M (g) ≤ 340
Answer:
15 degrees
Step-by-step explanation:
angle a= (180-90)/2=90/2=45 degrees
angle QRP = 60
Angle b = 60-45=15 degrees
C(t) = $2t + $8
This tells us that the basic cost of the pizza is $8, with no toppings, and that each topping costs an additional $2.
To graph this, plot a dot at (0,$8). Now move y our pencil point 1 unit to the right and then 2 units up. Plot a dot at this new location. Now draw a straight line connection (0, $8) and this new location (which is (1, $10) ).
![f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1} ](https://tex.z-dn.net/?f=f%28x%29%3D%5Cdisplaystyle%5Cfrac%7Bx%5E2%2Bx-2%7D%7Bx%2B1%7D%3D%5Cfrac%7Bx%28x%2B1%29-2%7D%7Bx%2B1%7D%3Dx-%5Cfrac%7B2%7D%7Bx%2B1%7D%0A)
![\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}} =0](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto%5Cinfty%7D%5Cleft%5C%7Bf%28x%29-x%20%5Cright%5C%7D%3D%5Clim_%7Bx%5Cto%5Cinfty%7D%5Cfrac%7B2%7D%7Bx%2B1%7D%3D%5Clim_%7Bx%5Cto%5Cinfty%7D%5Cfrac%7B%5Cdisplaystyle%5Cfrac%7B2%7D%7Bx%7D%7D%7B1%2B%5Cdisplaystyle%5Cfrac%7B1%7D%7Bx%7D%7D%0A%3D0)
Consequently, t<span>he limit of
![f(x)](https://tex.z-dn.net/?f=f%28x%29)
as x approaches infinity is
![x](https://tex.z-dn.net/?f=x)
.
In other words,
![f(x)](https://tex.z-dn.net/?f=f%28x%29)
approaches the line y=x,
</span><span>
so oblique asymptote is y=x.
I'm Japanese, if you find some mistakes in my English, please let me know.</span>