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2 years ago

A square room has a floor area of 81 square meters. The height of the room is 5 meters. What is the area of one wall

Mathematics

1 answer:

VMariaS [17]2 years ago

4 0

Area of a square is side length ^2

To find the length of the side of a square from the area, that’s the square root of the area:

Length of side = sqrt(81) = 9 meters

Area of wall = length of side x height:

Area of wall = 9 x 5 = 45 square meters

Answer: 45 square meters

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Will give brainliest

VikaD [51]

Answer: The number of the adult tickets is 168

Step-by-step explanation: * Lets explain how to solve the problem

- The adults ticket costs $10.50

- The students ticket costs $3.75

- The total money of the opening night is $2071.50

- The equation of the total money earned in the opening night is:

10.50 a + 3.75 b = 2071.50, where a is the number of the adult ticket

and b is the number of the student ticket

- There were 82 students attended

* Lets solve the problem

∵ 10.50 a + 3.75 b = 2071.50

∵ The number of the students attended is 82

∵ b is the number of the students

∴ b = 82

- Substitute the value of b in the equation

∴ 10.50 a + 3.75(82) = 2071.50

∴ 10.50 a + 307.5 = 2071.50

- Subtract 307.5 from both sides

∴ 10.50 a = 1764

- Divide both sides by 10.50

∴ a = 168

∵ a is the number of the adult tickets

∴ The number of the adult tickets is 168

Give credit to ashraf 82

8 0

2 years ago

Please answer ASAp I need this for my quiz ill give brainliest and ill thank you if its correct please i need a better grade .

zzz [600]

Answer:

I have made it in above picture

5 0

2 years ago

The perimeter of a rectangular swimming pool is 154m.Its length is 2m more than twice its breadth. What are the length and bread

TiliK225 [7]

$P = 154\\a = 2b + 2$

a = ?; b = ?

$P = 2(a + b) = 2(2b + 2 + b) = 2(3b + 2) = 6b + 4$

$154 = 6b + 4\\6b = 154 - 4\\6b = 150\\b = 150 : 6\\b = 25$

$a = 2b + 2 = 2 * 25 + 2 = 50 + 2 = 52$

Answer: 25 and 52 m.

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2 years ago

Please help! I'm having problems with deciding if 2.80 would be 2 or less or 2 or more.

Gekata [30.6K]

2.80 is more than 2, i would round it.

So sorry if this is wrong :(

7 0

3 years ago

Part a at what speed v should an archerfish spit the water to shoot down an insect floating on the water surface located at a di

loris [4]

3.01 m/s
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
V*sqrt(3)/2 ; Vertical velocity.
(V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
(V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.

The droplet's horizontal velocity will be:
V/2.

So the total distance the droplet travels will be:
d = (V*sqrt(3))/9.8 * V/2
d = V^2*sqrt(3)/19.6

Let's substitute the desired distance and solve for V
d = V^2*sqrt(3)/19.6
0.8 = V^2*sqrt(3)/19.6
15.68 = V^2*sqrt(3)
15.68/sqrt(3) = V^2
15.68/1.732050808 = V^2
3.008795809 = V
So after rounding to 3 significant figures, the archerfish needs to spit the water at a velocity of 3.01 m/s
Let's verify that answer.
Vertical velocity: 3.01 * sin(60) = 3.01 * 0.866025404 = 2.606736465
Time of flight = 2.606736465 * 2 / 9.8 = 0.531987034 seconds.
Horizontal velocity: 3.01 * cos(60) = 3.01 * 0.5 =

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3 years ago