We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where 
represents the number of objects/people in the set and 
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
I think it is 26 and 2
Step-by-step explanation:
39÷6=6.5
4×6.5=26
13÷6.5=2
If each years cumulate an increase of 1100 dollars, then the cost after 22 years will be the base cost (27000) plus 22 increases (22*1100), for a total of
This relates to arithmetic series as follows: a series is arithmetic if, given a starting element 
, every next element is given by adding a fixed number, called common difference, 
. So, the first terms are
So, you can see that the element 
is obtained by adding n times the common ratio to the starting element.
Since the element 
represents the cost after n years, we are interested in the element
As we had already calculated.
Answer:
we make 20&40 to be add.
Step-by-step explanation:
if we add 20&40
mean 20+40=60
so the answer is 60.
