The formula is:
Zn + Hcl —> H2 +Zncl2
Hence, the 2 products formed are:
Hydrogen gas and salt
Hope it helps!
Answer:
37064 J
Explanation:
Data Given:
mass of Steam (m) = 16.4 g
heat released (Q) = ?
Solution:
This question is related to the latent heat of condensation.
Latent heat of condensation is the amount of heat released when water vapors condenses to liquid.
Formula used
Q = m x Lc . . . . . (1)
where
Lc = specific latent heat of condensation
Latent heat of vaporization of water is exactly equal to heat of condensation with - charge
So, Latent heat of vaporization of water have a constant value
Latent heat of vaporization of water = 2260 J/g
So
Latent heat of condensation of water will be = - 2260 J/g
Put values in eq. 1
Q = (16.4 g) x (- 2260 J/g)
Q = - 37064 J
So, 37064 J of heat will be released negative sign indicate release of energy
The Independent Variable would be Amount of Sleep.
In BaF₂ the solubility will decreases on adding NaF
the solubility will increases on adding HCl
<h3>SOLUBILITY OF BARIUM FLUORIDE</h3>
- Increase in temperature will increase the solubility of the solid.
- By adding NaF - decrease the solubility of BaF₂
- By adding HCl - increase the solubility of BaF₂
<h3>BARIUM FLUORIDE</h3>
- It is colourless solid that occur as rare mineral
- It is corroded by moisture
- It is used in window of IR spectroscopy
Hence the barium fluoride the solubility decreases on adding NaF and increases on adding HCl.
Learn more about the solubility on
brainly.com/question/6841847
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Answer:
[tex]2KCl + Zn {}^{2 + } → 2K {}^{ + } + ZnCl _{2} \\ molecular \: mass \: of \: zinc \: chloride = 65 + (35.5 \times 2) = 136 \: g \\ molecular \: mass \: of \: potassium \: chloride = 39 + 35.5 = 74.5 \: g
