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Setler79 [48]
2 years ago
14

A 3.28 L solution is prepared by dissolving 535 g CaCl2 in water. The molar mass of CaCl2 is 110.98 g. What is the morality of t

he solution?
Chemistry
1 answer:
andrey2020 [161]2 years ago
5 0

Answer:

              1.47 mol/L

Explanation:

Molarity is given as,

                           Molarity = Moles / Vol in L    ------- (1)

Moles of CaCl₂,

                           Moles = Mass / M.Mass

                           Moles = 535 g / 110.98 g/mol

                           Moles = 4.82 mol

Now, putting values in eq. 1.

                           Molarity = 4.82 mol / 3.28 L

                           Molarity = 1.47 mol/L

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The chemical definitions of acids and bases for Arrhenius are:
Cloud [144]

Answer:

Explanation:

Arrhenius defined an acid as a substance that interacts with water to produce excess hydrogen ions in aqueous solution.

A base is a substance which interacts with water to yield excess hydroxide ions, in an aqueous solution according to Arrhenius.

Bronsted-Lowry theory defined an acid as a proton donor while a base is a proton acceptor.

6 0
3 years ago
According to the Law of Conservation of Matter, what happens to atoms of gas in a balloon when it is placed in the freezer?
scoundrel [369]

Answer:

the number of atoms stays the same as the atoms lose energy to the colder freezer, slow down, get closer together, shrinking the volume

Explanation:

When a liquid is cooled, the average energy of the molecules decreases. At some point, the amount of heat removed is great enough that the attractive forces between molecules draw the molecules close together, and the liquid freezes to a solid.

I hope it helps.

5 0
2 years ago
Equation Given : Al^(3+) + Na3PO4 ==> 3Na^+ + AlPO4
Helga [31]

1 mols of Aluminium ion forms 1 mol aluminium phosphate

Molar mass of AlPO_4

  • 27+31+16(4)
  • 58+48
  • 106u

Moles of AlPO_4

  • 61µg/106
  • 0.000061/106
  • 5.75×10^{-7}
  • 57.5µmol

Moles of Al3+=57.5µmol

3 0
3 years ago
15.0 mL of .275 M sulfuric acid solution "completely neutralizes" 20.0 mL of sodium hydroxide solution. What is the concentratio
gtnhenbr [62]

Answer:

The answer to your question is  0.415 M

Explanation:

Data

volume of H₂SO₄ = 15 ml

[H₂SO₄] = 0.275

volume of NaOH = 20 ml

[NaOH] = ?

Process

1.- Write the balanced chemical reaction

                    H₂SO₄  + 2NaOH   ⇒   Na₂SO₄  +  2H₂O

2.- Calculate the molar mass of H₂SO₄ and the molar mass of NaOH

molar mass of H₂SO₄ = 2 + 32 + (16 x 4) = 98g

molar mass of NaOH = 23 + 16 + 1 = 40 g

3.- Calculate the moles of H₂SO₄ in 15 ml

moles = Molarity x volume

moles = 0.275 x 0.015

moles = 0.0041

4.- Use proportions to calculate the moles of NaOH

                  1 mol of H₂SO₄ ----------------- 2 moles of NaOH

                 0.0041 moles    -----------------  x

                   x = (0.0041 x 2) / 1

                   x = 0.0083 moles of NaOH

5.- Calculate the molarity of NaOH

Molarity = moles/volume

Molarity = 0.0083/0.02

Molarity = 0.415

3 0
3 years ago
The symbol mm represents​
sladkih [1.3K]

Answer:

millimetre

Explanation:

7 0
3 years ago
Read 2 more answers
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