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Setler79 [48]
2 years ago
14

A 3.28 L solution is prepared by dissolving 535 g CaCl2 in water. The molar mass of CaCl2 is 110.98 g. What is the morality of t

he solution?
Chemistry
1 answer:
andrey2020 [161]2 years ago
5 0

Answer:

              1.47 mol/L

Explanation:

Molarity is given as,

                           Molarity = Moles / Vol in L    ------- (1)

Moles of CaCl₂,

                           Moles = Mass / M.Mass

                           Moles = 535 g / 110.98 g/mol

                           Moles = 4.82 mol

Now, putting values in eq. 1.

                           Molarity = 4.82 mol / 3.28 L

                           Molarity = 1.47 mol/L

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The volume of  0. 250 mole sample of H_{2} gas occupy if it had a pressure of 1. 70 atm and a temperature of 35 °C is  3.71 L.

Calculation,

According to ideal gas equation which is known as ideal gas law,

PV =n RT

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By putting all the values of the given data like pressure temperature universal gas constant and number of moles in equation (i) we get ,

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Here's what I get  

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