To answer this item, we may divide the given figure into two: (1) upper portion and (2) lower portion.
We solve first for the area of the lower portion figure, that is a rectangle with height equal to 1 unit and length of 5 units.
The area of a rectangle is calculated by multiplying its dimensions as shown in the formula below.
Area = Height x Length
Substituting,
Area = (1 unit) x (5 units) = 5 unit squared
Next, we have the second figure, upper portion. The length of this figure is given to be 2 units. The height is equal to 5 units - 1 unit because the 1 unit was already covered in the first figure. Thus, the height is equal to 4 units.
Solving for the area,
Area = (4 units)(2 units) = 8 units squared
Then, adding up both areas,
total area = (5 unit squared) + (8 unit squared) = 13 units squared
<em>ANSWER: 13 unit squared</em>
Start with the parent function f(x) = x³
Notice the function f(x) = (x - 4)³ that a value '4' is subtracted from 'x' ⇒ This means the function f(x) is translated four units to the right.
Then the function f(x) = ¹/₂ (x - 4)³, the function (x - 4)³ is halved vertically ⇒ Half the y-coordinate
Then the function f(x) = ¹/₂ (x - 4)³ + 5 that a value '5' is added to ¹/₂ (x - 4)³ ⇒ This means the function f(x) is translated five units up
So the order of transformation that is happening to f(x) = x³ is translation four units to the right, half the y-coordinate, then translate 5 units up.
Answer:
A
Step-by-step explanation:
The 3D shape of the 5 cubes put to a 2D-plane will be representing the diagram A.
I’m pretty sure it is 1/36!
we have
![2.9(x+8)< 26.1](https://tex.z-dn.net/?f=2.9%28x%2B8%29%3C%2026.1)
Solve the inequality
![2.9(x+8)< 26.1](https://tex.z-dn.net/?f=2.9%28x%2B8%29%3C%2026.1)
Divide both sides by ![2.9](https://tex.z-dn.net/?f=2.9)
![(x+8)< (26.1/2.9)](https://tex.z-dn.net/?f=%28x%2B8%29%3C%20%2826.1%2F2.9%29)
![(x+8)< 9](https://tex.z-dn.net/?f=%28x%2B8%29%3C%209)
Subtract
from both sides
![x< 9-8](https://tex.z-dn.net/?f=x%3C%209-8)
![x< 1](https://tex.z-dn.net/?f=x%3C%201)
the solution is the interval --------> (-∞,1)
therefore
<u>the answer is</u>
The solution in the attached figure