Answer:
Option A
Solution:
As per the question:
The distance covered by the woman in the North direction, d = 3000 m
Time taken to travel in North direction, t = 25.0 min = 1500 s
Velocity of woman in the south direction, v = 2.00 m/s
Time taken in the south direction, t' = 60.0 min = 3600 s
Now,
The distance covered in the south direction, d' = vt' = 
Now, the total displacement is given by:
D = d' - d = 7200 - 3000 = 4200 m in South
(a) Average velocity of the woman in the whole journey is given by:
≈ 0.824 m/s South
-- The vertical component of the ball's velocity is 14 sin(<span>51°) = 10.88 m/s
-- The acceleration of gravity is 9.8 m/s².
-- The ball rises for 10.88/9.8 seconds, then stops rising, and drops for the
same amount of time before it hits the ground.
-- Altogether, the ball is in the air for (2 x 10.88)/(9.8) = 2.22 seconds
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-- The horizontal component of the ball's velocity is 14 cos(</span><span>51°) = 8.81 m/s
-- At this speed, it covers a horizontal distance of (8.81) x (2.22) = <em><u>19.56 meters</u></em>
before it hits the ground.
As usual when we're discussing this stuff, we completely ignore air resistance.
</span>
Answer:
A path that allows most of the current in an electric circuit to flow around or away from the principal elements or devices in the circuit.
