what is the mechanical advantage of a machine that uses an input force of 20 newtons to achieve an output force of 60 newtons

WILL GIVE BRAINLIEST HELP FASTWhat is the mass of Planet X? Note: The constant of universal gravity (G) equals 6.674 X 10-11 N·m

disa [49]

Answer:

Explanation:

Centripetal acceleration's equation is:

$a_c=\frac{v^2}{r}$ where v is the velocity of the object (moon II) and r is the radius. We have the radius, but we don't have the velocity, and we can't solve for acceleration until we do have it. Assuming moon II is a circle, or close enough to be called a circle, it has a circumference.

C = 2πr. If we can find the circumference of the circle, we can plug in the orbital period for the time, the circumference for the distance, and solve for velocity in d = rt. So let's do that and see what happens.

C = 2(3.14)(9.0 × 10⁷) and

C = d = 5.7 × 10⁸. Plugging in and solving for v:

$5.7*10^8=v(3.0*10^5)$ and

v = 1.9 × 10³. That is the velocity we can use in the centripetal acceleration equation.

$a_c=\frac{(1.9*10^3)^2}{9.0*10^7}$ and

$a_c=.040\frac{m}{s^2}$

These are fun!

8 0

3 years ago

An object that is 3 times higher than another object of the same mass will

uranmaximum [27]

Answer: I feel that 3 is the answer

Explanation: Let there be 2 objects, A and B

A is at height of 5m whereas B is at height of 15m

so over here let the gravitational potential energy of A be x

and since B is 3 times higher than A B=3x

Since, earth is considered to be the point where gravitational potenial is 0

So hence forth and object 3 times up will have 3 times the gravitational potential energy of A

3 0

3 years ago

A 0.35-kgkg cord is stretched between two supports, 7.4 mm apart. When one support is struck by a hammer, a transverse wave trav

Agata [3.3K]

Answer:

The tension in the string is $T = 1.49*10^{-6}N$ .

Explanation:

For a string with tension $T$ and linear density $\mu_d$ carrying a transverse wave at speed $v$ it is true that

$v = \sqrt{\dfrac{T}{\mu_d} }$

solving for $T$ we get:

$T = \dfrac{v^2}{\mu_d}.$

Now, the transverse wave covers the distance of 7.4mm in 0.88s, which means it's speed is

$v =\dfrac{7.4*10^{-3}m}{0.88s} \\\\v = 8.4*10^{-3}s$

And it's linear density (mass per unit length) is

$\mu_d = \dfrac{0.35kg}{7.4*10^{-3}m} \\\\\mu_d = 47.3kg/m$

Therefore, the tension in the cord is

$T = \dfrac{(8.4*10^{-3}m/s^2)^2}{47.3kg/m}.$

$\boxed{T = 1.5*10^{-6}N}$

or in micro newtons

$T =1.5\mu N$

4 0

3 years ago

If someone is driving 100 miles in 60 minutes then drives 150 miles in 100 minutes west, what is his acceleration rate.

Sliva [168]

Answer:

his acceleration rate is -0.00186 m/s²

Explanation:

Given;

initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)

time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s

final position of the car, x₁ = 150 miles = 241,350 m

time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s

The initial velocity is calculated as;

u = 160, 900 m / 3,600 s

u = 44.694 m/s

The final velocity is calculated as;

v = 241,350 m / 6,000 s

v = 40.225 m/s

The acceleration is calculated as;

$a = \frac{\Delta V}{\Delta t} = \frac{v- u}{t_1 - t_ 0} = \frac{40.225 - 44.694}{6000-3600} = -0.00186 \ m/s^2\\\\$

Therefore, his acceleration rate is -0.00186 m/s²

6 0

3 years ago

What do hydrogen and helium have in common?

Savatey [412]

Atomic disguise makes helium look like hydrogen. ... A helium atom consists of a nucleus containing two positively charged protons and two neutrons, encircled by two orbiting electrons which carry a negative charge. A hydrogen atom has just one proton and one electron

4 0

3 years ago