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kari74 [83]
3 years ago
14

An atomic number stands for the number of _____. neutrons in the nucleus of an atom protons in the nucleus of an atom valence el

ectrons in an atom protons plus neutrons in the nucleus of an atom
Chemistry
1 answer:
Effectus [21]3 years ago
5 0

Answer:

atoms or electrons

Explanation:

but l guess electrons is the best answer

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Is eubacteria a multicellular organism or a unicellular organism?
jasenka [17]
Eubacteria is a unicellular organism because they are made of one cell. Hope this helps! :)
8 0
3 years ago
The volume of a sample of gas is 0.5 L and the pressure is 0.98 atm. The volume is increased to 1.0 L. Show the set
meriva

Given,

P1 = 0.98 atm

V1 = 0.5 L

V2 = 1.0 L

P2 = ?

Solution,

According to Boyle's Law,

P1V1 = P2V2

0.98 × 0.5 = 1.0 × P2

P2 = 0.98 × 0.5 × 1.0

P2 = 0.49 atm

Answer - The new pressure is 0.49 atm.

5 0
3 years ago
Pls help
Simora [160]

Heat required to raise the temperature = 159.505 J

<h3>Further explanation</h3>

Given

c = specific heat of Beryllium = 1.825 J/g C

m = mass = 2.3 g

Δt = Temperature difference : 60 - 22 = 38 °C

Required

Heat required

Solution

Heat can be formulated

Q = m.c.Δt

Input the value :

Q = 2.3 x 1.825 x 38

Q = 159.505 J

8 0
2 years ago
How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
Alona [7]

Answer:

Approximately 1.95 \times 10^{2}\; \rm J.

Explanation:

Look up the specific heat of gaseous neon:

c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}.

Calculate the required temperature change:

\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Let m denote the mass of a sample of specific heat C. Energy required to raise the temperature of this sample by \Delta T:

Q = c \cdot m \cdot \Delta T.

For the neon gas in this question:

  • c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}.
  • m = 10.6\; \rm g.
  • \Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Calculate the energy associated with this temperature change:

\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}.

3 0
3 years ago
Is one mole of zinc the same as one atom of zinc?
Papessa [141]

Answer: No.

Explanation: One mole of zinc is not the same as one atom of zinc. In one mole of zinc, there are approximately 6.022*10^23 atoms of zinc.

3 0
3 years ago
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