Basic radicals (cations) have been divided into groups based on Ksp values
Atomic Number of Lithium is 3, so it has 3 electrons in its neutral state. Also, Li₂ will have 6 electrons. But the chemical formula we are given has a negative charge on it (i.e Li₂⁻) so there is an additional electron (RED) present on this compound. So, the total number of electrons are 7. The
MOT diagram for this compound is shown below. According to diagram we are having 4 electrons in Bonding Molecular Orbitals (
BMO) and 3 electrons in Anti-Bonding Molecular Orbitals (
ABMO). Bond Order is calculated as,
Bond Order = (# of e⁻s in BMO - # of e⁻s in ABMO) ÷ 2
Bond Order = (4 - 3) ÷ 2
Bond Order = 1 ÷ 2
Or,
Bond Order = 1/2Or,
Bond Order = 0.5
Answer: There are
atoms present in 0.500 mol of
.
Explanation:
According to the mole concept, there are
atoms present in 1 mole of a substance.
In a molecule of
there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of
are as follows.

Thus, we can conclude that there are
atoms present in 0.500 mol of
.
Density = Mass ÷ Volume. You get 2.466
<span>Heavier atoms make denser materials</span>