Answer:
5.17.
Explanation:
<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.
</em>
[OH⁻] = 1.5 x 10⁻⁹ M.
∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(1.5 x 10⁻⁹ M) = 6.66 × 10⁻⁶ M.
∵ pH = - log[H₃O⁺]
<em>∴ pH = - log(6.66 × 10⁻⁶ M) = 5.17.
</em>
A catalyst speeds up the rate of reaction so the answer is B.
The answers would be the mass before a reaction is the same as the mass after a reaction which basically means mass is conserved
Answer:
copper I oxide
Explanation:
Copper is known to form two oxides; copper I oxide and copper II oxide.
In the question we have the ions; Cu1+ and O2-. Ionic compounds are formed by a combination of ions as typified below;
Cu^+ + O^2- -------> Cu2O
This compound is copper I oxide
Answer:
29% is the final concentration
Explanation:
To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:
Volume ethanol / Total volume * 100
<em>Volume ethanol:</em>
10mL * 70% = 7mL ethanol
+
20mL * 80% = 16mL ethanol
= 23mL ethanol
<em>Total volume:</em>
10mL + 20mL + 50mL = 80mL
<em>Concentration:</em>
23mL / 80mL * 100
= 29% is the final concentration
