The diagonal of a square is equal to the side x times square root of 2, xSqrt(2)
z = xSqrt(2), its rate of change is just Sqrt(2)
Answer:(1,1)
Step-by-step explanation:
y=4.5x
x=y/4.5
put value of x
y=4.5(y/4.5)
y=y
Answer:
10x^3 + 6x^2 + 5x + 3
Step-by-step explanation:
F(x)=(5x+3)(2x^2+1)
= 5x*2x^2 + 5x*1 + 3*2x^2 + 3*1
= 10x^3 + 5x + 6x^2 + 3
= 10x^3 + 6x^2 + 5x + 3
Answer:
b=4
Step-by-step explanation:
So, we have the function
. We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).
f(2) = 1/(2) = 1/2
So, we have the point (2, 1/2)
At point b, f(b) = 1/b.
Let's plug this into the slope formula:

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

Now, cross multiply.


Solve for b. Factor using the numbers -4 and -2.

Thus, b=4 or b=2.
However, b=2 is not a possible solution since the interval [2,2] means nothing. Thus, b=4.