Question

A 960 kg car initially moving at 30.0 m/s hits a 150-kg deer initially running at 12.0 m/s in the same direction. After the hitting. the deer remains on the car. What is the final velocity (in m/s)?

Answer 1

Answer:

V = 27.56 m/s

Explanation:

It is given that,

Mass of the car, $m_1=960\ kg$

Initial speed of the car, $u_1=30\ m/s$

Mass of the deer,  $m_2=150\ kg$  

Initial speed of the deer, $u_2=12\ m/s$

It is mentioned that after the hitting. the deer remains on the car. It is a case of inelastic collision. Let V is the speed of final speed of the deer and the car. Using the conservation of momentum to find it as :

$m_1u_1+m_2u_2=(m_1+m_2)V$

$V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}$

$V=\dfrac{960\times 30+150\times 12}{(960+150)}$

V = 27.56 m/s

So, the final velocity of the deer and the car is 27.56 m/s.