The normal force acting on April as she stands on a flat surface is 705.6 N.
Normal force of the girl
Fₙ = mg
where;
- Fₙ is the normal force of the girl
- m is mass of the girl
- g is acceleration due to gravity
Fₙ = 72 x 9.8
Fₙ = 705.6 N
Thus, the normal force acting on April as she stands on a flat surface is 705.6 N.
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Answer:
Atomic number of the daughter isotope = (Atomic number of the parent isotope) - 4
Explanation:
An alpha particle has atomic number of 2 and a mass number of 4
Losing two alpha particles would lead to a reduction of 4 in atomic number and 8 in mass number for the radioactive isotope, to give the stable daughter isotope.
Answer:
Explanation:
In a frictionless system with no acceleration, the tension in the rope must be F along its entire length
FBD analysis of the lower pulley has two upward acting tension vectors F and one downward acting weight vector W
2F = W
F = W/2
FBD analysis of the upper pulley has one upward acting support vector T and three downward acting tension vectors F
T = 3F
T = 3(W/2)
T = 1.5W