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AleksandrR [38]
3 years ago
5

An N-slit system has slit separation d and slit width a. Plane waves with intensity I and wavelength O are incident normally on

it. The angular separation of the lines depends only on:
A. a and N. B. I and N. C. N and O. D. a and O. E. d and O
Physics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

E. d and O

Explanation:

"Light passing through a single slit forms a diffraction pattern somewhat different from those formed by double slits or diffraction gratings".

According to Huygens’s principle, "for each element of the wavefront in the slit emits wavelets. These are like rays that start out in phase and head in all directions. (Each ray is perpendicular to the wavefront of a wavelet.) Assuming the screen is very far away compared with the size of the slit, rays heading toward a common destination are nearly parallel".

The destructive interference for a single slit is given by:

d sin \theta = m\lambda , m=1,-1,2,-2,3,...

Where

d is the slit width

\lambda=O is the light's wavelength

\theta is the angle relative to the original direction of the light

m is the order od the minimum

I represent the intensity

When the intensity and the wavelength are incident normally the angular as we can see on the expression above the angular separation just depends of the distance d and the wavelength O.

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vekshin1

The electric field at (x,y,z) its equal to the negative of the gradient if the electric potential.

We have

V(x, y, z) = 2x² - 3y² + 5z

so

E(x, y, z) = -grad(V) = -(dV/dx i + dV/dy j + dV/dz k)

where d/d(variable) is meant to be a partial derivative with respect to that variable. The partial derivatives are

dV/dx = 4x

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dV/dz = 5

and so the electric field at any point is

E(x, y, z) = -4x i + 6y j - 5k

and at (3, 4, 5) it is

E(3, 4, 5) = -12i + 24j - 5k

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3 years ago
If frequency increases, then wavelength _________.
umka21 [38]

Answer:

Decrease

Explanation:

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At the end of a delivery ramp, a skid pad exerts a constant force on a package so that the package comes to rest in a distance d
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increases by a factor of \sqrt{2}

Explanation:

First we need to find the initial velocity for it to stop at the distance 2d using the following equation of motion:

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where v = 0 m/s is the final velocity of the package when it stops, v_0 is the initial velocity of the package when it, a is the deceleration, and \Delta s = d is the distance traveled.

So the equation above can be simplified and plug in Δs = d, v_0 = v_1 for the 1st case

-v_1^2 = 2ad(1)

For the 2nd scenario where the ramp is changed and distance becomes 2d, v_0 = v_2

-v_2^2 = 4ad(2)

let equation (2) divided by (1) we have:

\left(\frac{v_2}{v_1}\right)^2 = 4ad / 2ad = 2

v_2 / v_1 = \sqrt{2}

v_2 = \sqrt{2}v_1

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4 years ago
Which single force acts on a object in a free fall
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4 0
3 years ago
What is the wavelength of a light ray that has a frequency of 7.4 E12 Hz?
const2013 [10]

The wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.

Given the data in the question;

  • Frequency of the light ray; f = 7.4 * 10^{12}Hz
  • Wavelength; \lambda = \ ?

<h3>Wavelength</h3>

Wavelength can be simply defined as the spatial period of a periodic wave. When the shapes of waves are repeated, the distance over which they are repeated is called wavelength. Wavelength is expressed as;

\lambda = \frac{c}{f}

Where \lambda is wavelength, f is frequency and c is speed of light( c = 3*10^8m/s )

We substitute our values into the expression above to determine the wavelength of the light ray.

\lambda = \frac{c}{f} \\\\\lambda = \frac{3*10^8m/s}{7.4*10^{12}s^{-1}}} \\\\\lambda = \frac{3*10^8ms/s}{7.4*10^{12}}}\\\\\lambda = 4.05*10^{-5}m\\\\\lambda = 4.05*10^{4}nm

Therefore, the wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.

Learn more about wavelength: brainly.com/question/16776907

5 0
2 years ago
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