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AleksandrR [38]
3 years ago
5

An N-slit system has slit separation d and slit width a. Plane waves with intensity I and wavelength O are incident normally on

it. The angular separation of the lines depends only on:
A. a and N. B. I and N. C. N and O. D. a and O. E. d and O
Physics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

E. d and O

Explanation:

"Light passing through a single slit forms a diffraction pattern somewhat different from those formed by double slits or diffraction gratings".

According to Huygens’s principle, "for each element of the wavefront in the slit emits wavelets. These are like rays that start out in phase and head in all directions. (Each ray is perpendicular to the wavefront of a wavelet.) Assuming the screen is very far away compared with the size of the slit, rays heading toward a common destination are nearly parallel".

The destructive interference for a single slit is given by:

d sin \theta = m\lambda , m=1,-1,2,-2,3,...

Where

d is the slit width

\lambda=O is the light's wavelength

\theta is the angle relative to the original direction of the light

m is the order od the minimum

I represent the intensity

When the intensity and the wavelength are incident normally the angular as we can see on the expression above the angular separation just depends of the distance d and the wavelength O.

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Answer:

Angle θ = 30.82°

Explanation:

From Malus’s law, since the intensity of a wave is proportional to its amplitude squared, the intensity I of the transmitted wave is related to the incident wave by; I = I_o cos²θ

where;

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In this question,

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While I_o is 0.960 W/m²

Thus, plugging in these values into the equation, we have;

0.708 W/m² = 0.960 W/m² •cos²θ

Thus, cos²θ = 0.708 W/m²/0.960 W/m²

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Cos θ = √0.7375

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<h3><u>Answer;</u></h3>

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Read 2 more answers
PLEASE HELP!!
dedylja [7]
Pretty sure it’s A. Hope this helps.
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