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spayn [35]
3 years ago
10

Which is the best approximation to a solution of the equation e^x = 2x + 3?

Mathematics
1 answer:
TiliK225 [7]3 years ago
3 0
The correct question is 
Which is the best approximation to a solution of the equation
e^(2x) = 2e^{x) + 3?

we have that

e^(2x) = 2e^{x) + 3-----------> e^(2x)- 2e^{x) - 3=0
the term 
e^(2x)- 2e^{x)----------> (e^x)²-2e^(x)*(1)+1²-1²------> (e^x-1)²-1

then
e^(2x)- 2e^{x) - 3=0--------> (e^x-1)²-1-3=0------> (e^x-1)²=4
(e^x-1)=2--------> e^x=3
x*ln(e)=ln(3)---------> x=ln(3)
ln(3)=1.10
hence
x=1.10

the answer is x=1.10



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Which polynomial is equal to  (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x)?

<h3><u><em>Answer:</em></u></h3>

The polynomial equal to (-3x^2 + 2x - 3) subtracted from  (x^3 - x^2 + 3x) is x^3 + 2x^2 + x + 3

<h3><u><em>Solution:</em></u></h3>

Given that two polynomials are: (-3x^2 + 2x - 3) and (x^3 - x^2 + 3x)

We have to find the result when (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x)

In basic arithmetic operations,

when "a" is subtracted from "b" , the result is b - a

Similarly,

When (-3x^2 + 2x - 3) is subtracted from  (x^3 - x^2 + 3x) , the result is:

\rightarrow (x^3 - x^2 + 3x) - (-3x^2 + 2x - 3)

Let us solve the above expression

<em><u>There are two simple rules to remember: </u></em>

  • When you multiply a negative number by a positive number then the product is always negative.
  • When you multiply two negative numbers or two positive numbers then the product is always positive.

So the above expression becomes:

\rightarrow (x^3 - x^2 + 3x) + 3x^2 -2x + 3

Removing the brackets we get,

\rightarrow x^3 - x^2 + 3x + 3x^2 -2x + 3

Combining the like terms,

\rightarrow x^3 -x^2 + 3x^2 + 3x - 2x + 3

\rightarrow x^3 + 2x^2 + x + 3

Thus the resulting polynomial is found

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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