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GaryK [48]
3 years ago
7

A giant tortoise can walk about 1/10 meter per second on land. A cooter turtle can walk about 1/2 meter per second on land. How

long would it take a giant tortoise to travel 5 meters? How much longer would it take a giant tortoise than a cooter turtle to travel 10 meters on land?
Mathematics
1 answer:
galina1969 [7]3 years ago
6 0
The rate of giant tortoise is 1/10 meters per each second.
The rate of cooter turtle is 1/2 meters per each second.

How long would it take a giant <span>tortoise to travel 5 meters?
1 second : 1/10 m = X : 5 m
1/10x = 5
x = 50 seconds

How much longer would it take a giant tortoise than a cooter turtle to travel 10 meters on land?
1 second : 1/2 m = X : 10 m
1/2x = 10
x = 20 seconds

So the giant turtle can travel 5 meters in 50 seconds.
</span><span>So the cooter turtle can travel 10 meters in 20 seconds.</span>
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The polar coordinates of a point are 3π 4 and 7.00 m. What are its Cartesian coordinates (in m)? (x, y) = 6.06,−3.5 m
Keith_Richards [23]

Answer:

a) \left(x,y\right)=\left(4.95,-4.95\right)

b) r\angle\theta = 7\angle0.5236\,\text{radians}

Step-by-step explanation:

Polar coordinates are represented as: r\angle\theta, where 'r' is the length (or magnitude) of the line, and '\theta' is the angle measured from the positive x-axis.

in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

\left(x,y\right)=\left(4.95,-4.95\right)

(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

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