let's put value of t in equation.
x = 2√t
x = 2√y
x/2 = √y
(x/2)^2 = y
y = x^2 /4
now let's differentiate it with respect to x.
dy/dx = 2x/4 = x/2
differentiating again wrt to x
d^2y/dx^2 = 1/2
<span>The area of the square is d^2. The area of the circle sandbox is πr^2=πd^2/4. So the area of play area only is equal to square area minus circle area which is d^2-πd^2/4.</span>
Answer:

Step-by-step explanation:
<u>Step 1: Set x to -1 and solve</u>
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Answer: 
Answer:
C. -7x^2 - 28
Step-by-step explanation:
Firstly simplify the bracket before doing anything;
4x(3x - 7) = 12x^2 - 28x
then go back to the question and substitute the expression(12x^2 - 28x) on the bracket and then work out the question;
12x^2 - 28x -19x^2...then group the values with the same exponent of x,
(12x^2 - 19x^2) - 28x
; -7x^2 - 28x