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Answer:
The required point is P(-7,) where, x-coordinate twice the y-coordinate on line 2x - 6y = 7
Step-by-step explanation:
Given equation of line is 2x-6y=7
To find point on graph whose x-coordinate twice the y-coordinate:
Let y be y-coordinate of point
Hence, x-coordinate of point will be 2y
The required point is P(2y,y) on equation of line 2x-6y=7
Now,
2x-6y=7
2(2y)-6y=7
-2y=7
y=
Thus,
The required point is P(-7,)
Note: Figure show equation of line red line and point P as blue dot.
Answer:
A. (2x-3)/2
Step-by-step explanation:
Performing the long division indicated by the perimeter expression, you find ...
perimeter = (2x -3) + (10x +6)/(x^2 +2x)
Comparing this to the formula for the perimeter ...
perimeter = 2W +2L
where L is said to be of the form (ax +b)/(x^2 +2x)
we can match terms in the perimeter expression to see that ...
2W = 2x -3
2L = (10x +6)/(x^2 +2x)
The problem doesn't ask for it, but we can see that (a, b) = (5, 3). We can also see that ...
W = (2x -3)/2 . . . . . . . matches choice A
