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yanalaym [24]
2 years ago
13

Please help me and fast

Mathematics
1 answer:
bagirrra123 [75]2 years ago
4 0

Answer:

its A

Step-by-step explanation:

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A jury pool consists of 50 potential jurors and how many ways can a jury of 12 be selected
bija089 [108]

Solution:

we are given that

A jury pool consists of 50 potential jurors.

Wee have been asked to find the number of ways can a jury of 12 be selected.

As we know from the concept of combination that r person can be selected out of n in ncr ways. where

n_C_r=\frac{n!}{r!(n-r)!}

Now substitute the values we get

{50}_C_{12}=\frac{50!}{12!(50-12)!}\\
\\
{50}_C_{12}=\frac{50!}{12!38!}\\
\\
{50}_C_{12}=121399651100\\

Hence the required number of ways is 121399651100

5 0
3 years ago
-8=-(x+4). Please help I don't know the answer or steps to solve this equation.
Ne4ueva [31]

Answer:

x = 4

Step-by-step explanation:

First u need to distribute the -1 to (x + 4), creating the equation, -8 = -x - 4. Then add the -4 to both sides, and you get, -4 = -x. Then divide by -1 to both sides, and x = 4.

6 0
3 years ago
Read 2 more answers
Please help due tomorrow Fri
ch4aika [34]
5 feet is the answer
3 0
3 years ago
Read 2 more answers
The figure below shows a rectangle ABCD having diagonals AC and DB: A rectangle ABCD is shown with diagonals AC and BD. Jimmy wr
yaroslaw [1]

Answer:

C. DC = DC. By reflexive property of equality.

Step-by-step explanation:

We are given that,

In step 4, Jimmy proved ΔADC ≅ ΔBCD by the SAS Congruence Postulate.

For that, the previous steps states,

Step 1: AD = BC, as opposite sides of a rectangle are congruent.

Step 2: ∠ADC = ∠BCD

So, in order to satisfy the SAS Postulate, we must have another pair of sides equal from the respective rectangles.

As, we can see that in ΔADC and ΔBCD, the side DC is a common side.

Thus, in the missing step, we get,

Step 3: DC = DC, By the reflexive property of equality.

Hence, option C is correct.

5 0
3 years ago
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Pls someone answer pls :)
Goshia [24]

Answer:

(-x-2) (-2x -3)=0

=>[-(x +2)] [-(2x+3)]=0

=>(x + 2)(2x +3)=0

=>x =-2 or,x=-3/2

smaller x=-2

larger x =-3/2

3 0
3 years ago
Read 2 more answers
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